# Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 4)
4.
A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B?
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Explanation:

Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years. (2x + 2) + 2x + x = 27 5x = 25 x = 5.

Hence, B's age = 2x = 10 years.

Discussion:
74 comments Page 1 of 8.

Sanju said:   3 months ago
A = B+2.
C = B/2 (OR) B=2C.

WE KNOW THAT [A+B+C =27].
(B+2)+B+(B/2)=27,
2B+4+2B+B=54,
5B =54-4,
5B=50,
B=50/5,
B=10.
(2)

Chandra hero said:   8 months ago
B - A = A - C.
B = 20/2.
= 10.
(1)

Rakesh said:   2 years ago
A = 2+B.
B = 2C,
A+B+C = 27.

2 + 2C + 2C + C = 27
5C = 27 - 2,
5C = 25,
C = 5.

JANAKIRAM said:   2 years ago
A = B+2
B = 2C = >C=B/2
A + B + C = 27.

Substitute A & C values in above equation
B + 2 + B + B/2 = 27.
5B/2 = 25.
B = 10.
(2)

Tanishq said:   3 years ago
a = two years more than b+2.
b = twice on c 2x.
Assume c = x.

b+2+2x+x.

Substitute b.
2x+2+2x+x = 5x.
5x = 27-2.
x = 5.
b = 2*5 = 10.
(2)

Nikunj said:   3 years ago
Simply, the solution is
(x+2) + x + 0.5x = 27.
x + x + 0.5x = 25.
x = 10.
(1)

Sam said:   3 years ago
Let.

C's age = x,
B's age = 2x,
A's age = 2x + 2.

X +2x+ 2x+2=27.
5x +2=27,
5x =25,
X=5.
B's Age= 2x.
2*5 = 10.
(2)

Sahas said:   3 years ago
a = two years more than b+2.
b = twice on c 2x.
Assume c = x.

b+2+2x+x.
Substitute b.
2x+2+2x+x=5x.
5x= 27-2.
x=5.
b = 2*5 = 10.

Dinesh said:   3 years ago
It is simple just separate it as 3, 9 + 9 + 9 = 27 it is simple.

Mihret said:   3 years ago
Thank you @Shan.