# Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 4)

4.

A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B?

Answer: Option

Explanation:

Let C's age be *x* years. Then, B's age = 2*x* years. A's age = (2*x* + 2) years.

(2*x* + 2) + 2*x* + *x* = 27

5*x* = 25

*x* = 5.

Hence, B's age = 2*x* = 10 years.

Discussion:

74 comments Page 1 of 8.
Sanju said:
3 months ago

A = B+2.

C = B/2 (OR) B=2C.

WE KNOW THAT [A+B+C =27].

(B+2)+B+(B/2)=27,

2B+4+2B+B=54,

5B =54-4,

5B=50,

B=50/5,

B=10.

C = B/2 (OR) B=2C.

WE KNOW THAT [A+B+C =27].

(B+2)+B+(B/2)=27,

2B+4+2B+B=54,

5B =54-4,

5B=50,

B=50/5,

B=10.

(2)

Chandra hero said:
8 months ago

B - A = A - C.

B = 20/2.

= 10.

B = 20/2.

= 10.

(1)

Rakesh said:
2 years ago

A = 2+B.

B = 2C,

A+B+C = 27.

2 + 2C + 2C + C = 27

5C = 27 - 2,

5C = 25,

C = 5.

B = 2C,

A+B+C = 27.

2 + 2C + 2C + C = 27

5C = 27 - 2,

5C = 25,

C = 5.

JANAKIRAM said:
2 years ago

A = B+2

B = 2C = >C=B/2

A + B + C = 27.

Substitute A & C values in above equation

B + 2 + B + B/2 = 27.

5B/2 = 25.

B = 10.

B = 2C = >C=B/2

A + B + C = 27.

Substitute A & C values in above equation

B + 2 + B + B/2 = 27.

5B/2 = 25.

B = 10.

(2)

Tanishq said:
3 years ago

a = two years more than b+2.

b = twice on c 2x.

Assume c = x.

b+2+2x+x.

Substitute b.

2x+2+2x+x = 5x.

5x = 27-2.

x = 5.

b = 2*5 = 10.

b = twice on c 2x.

Assume c = x.

b+2+2x+x.

Substitute b.

2x+2+2x+x = 5x.

5x = 27-2.

x = 5.

b = 2*5 = 10.

(2)

Nikunj said:
3 years ago

Simply, the solution is

(x+2) + x + 0.5x = 27.

x + x + 0.5x = 25.

x = 10.

(x+2) + x + 0.5x = 27.

x + x + 0.5x = 25.

x = 10.

(1)

Sam said:
3 years ago

Let.

C's age = x,

B's age = 2x,

A's age = 2x + 2.

X +2x+ 2x+2=27.

5x +2=27,

5x =25,

X=5.

B's Age= 2x.

2*5 = 10.

C's age = x,

B's age = 2x,

A's age = 2x + 2.

X +2x+ 2x+2=27.

5x +2=27,

5x =25,

X=5.

B's Age= 2x.

2*5 = 10.

(2)

Sahas said:
3 years ago

a = two years more than b+2.

b = twice on c 2x.

Assume c = x.

b+2+2x+x.

Substitute b.

2x+2+2x+x=5x.

5x= 27-2.

x=5.

b = 2*5 = 10.

b = twice on c 2x.

Assume c = x.

b+2+2x+x.

Substitute b.

2x+2+2x+x=5x.

5x= 27-2.

x=5.

b = 2*5 = 10.

Dinesh said:
3 years ago

It is simple just separate it as 3, 9 + 9 + 9 = 27 it is simple.

Mihret said:
3 years ago

Thank you @Shan.

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