Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 4)

Problems on Ages

A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B?

Answer: Option

Explanation:

Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.

(2x + 2) + 2x + x = 27

5x = 25

x = 5.

Hence, B's age = 2x = 10 years.

Discussion:

79 comments Page 2 of 8.

Nikunj said: 5 years ago

Simply, the solution is
(x+2) + x + 0.5x = 27.
x + x + 0.5x = 25.
x = 10.

(1)

Sam said: 5 years ago

Let.

C's age = x,
B's age = 2x,
A's age = 2x + 2.

X +2x+ 2x+2=27.
5x +2=27,
5x =25,
X=5.
B's Age= 2x.
2*5 = 10.

(7)

Sahas said: 6 years ago

a = two years more than b+2.
b = twice on c 2x.
Assume c = x.

b+2+2x+x.
Substitute b.
2x+2+2x+x=5x.
5x= 27-2.
x=5.
b = 2*5 = 10.

(3)

Dinesh said: 6 years ago

It is simple just separate it as 3, 9 + 9 + 9 = 27 it is simple.

Mihret said: 6 years ago

Thank you @Shan.

Venkata ramana said: 6 years ago

A = B+2
B = 2C
A+B+C = 27,(B+2)+2C+C = 27,B+2+3C = 27, B+3C = 25, 2C+3C = 25,5C = 25, C = 5.
Then B is twice as old as C, B = 2C, B = 2(5) = 10.

Onkar said: 6 years ago

A+B+C=27 --->(1)
A-B=2.
B=2C.
A-2C=2 --> (2).

SUBTRACT eqn 1 from 2 .
B + 3C = 25.
BUT B = 2C C = 5.
B = 10 A = 12.

Sony said: 6 years ago

Older means it should be age of A is x-2x, is it?

Mahesh bist said: 6 years ago

Here, let B= x then A= 2+x then always c= x/2.
According to question,
A+B+C = 27,
(2+x)+x+x/2 = 27,
5x+4 = 27*2,
x = 50/5,
x = 10.

Zeeshan Ali said: 7 years ago

Thanks all for explaining the answer clearly.

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