Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 4)
4.
A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B?
Answer: Option
Explanation:
Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25
x = 5.
Hence, B's age = 2x = 10 years.
Discussion:
79 comments Page 1 of 8.
RAJU RONGPI said:
2 years ago
A= 2+B ---> 1
B=2C --->2.
A+B+C = 27
2 + B + 2C+ B/2 = 27.
2 + B + 2.B/2+B/2 = 27.
2B + B/2 = 25
4B + B = 50,
Then, B = 10.
B=2C --->2.
A+B+C = 27
2 + B + 2C+ B/2 = 27.
2 + B + 2.B/2+B/2 = 27.
2B + B/2 = 25
4B + B = 50,
Then, B = 10.
(15)
Sanju said:
3 years ago
A = B+2.
C = B/2 (OR) B=2C.
WE KNOW THAT [A+B+C =27].
(B+2)+B+(B/2)=27,
2B+4+2B+B=54,
5B =54-4,
5B=50,
B=50/5,
B=10.
C = B/2 (OR) B=2C.
WE KNOW THAT [A+B+C =27].
(B+2)+B+(B/2)=27,
2B+4+2B+B=54,
5B =54-4,
5B=50,
B=50/5,
B=10.
(10)
Isha hugar said:
2 years ago
Yes, agree, 10 is the right answer.
(9)
Rakesh said:
4 years ago
A = 2+B.
B = 2C,
A+B+C = 27.
2 + 2C + 2C + C = 27
5C = 27 - 2,
5C = 25,
C = 5.
B = 2C,
A+B+C = 27.
2 + 2C + 2C + C = 27
5C = 27 - 2,
5C = 25,
C = 5.
(8)
Annn said:
8 months ago
A + B + C = 27.
B = A + 2.
C = 2B.
A + (A+2) + 2(A+2) = 27,
4A + 6 = 27,
A = 5.
B = 7.
B = A + 2.
C = 2B.
A + (A+2) + 2(A+2) = 27,
4A + 6 = 27,
A = 5.
B = 7.
(7)
Oro Oghenevwegba said:
12 months ago
A + B + C = 27,
A = 2 + B,
B = 2C,
B = x.
Equate the above into A + B + C = 27.
2 + 2C + 2C + C = 27.
2 + 5C = 27.
5C/5 = 25/5.
C = 5.
B = 2C.
B = 2×5 = 10.
A = 2 + B,
B = 2C,
B = x.
Equate the above into A + B + C = 27.
2 + 2C + 2C + C = 27.
2 + 5C = 27.
5C/5 = 25/5.
C = 5.
B = 2C.
B = 2×5 = 10.
(7)
Sam said:
5 years ago
Let.
C's age = x,
B's age = 2x,
A's age = 2x + 2.
X +2x+ 2x+2=27.
5x +2=27,
5x =25,
X=5.
B's Age= 2x.
2*5 = 10.
C's age = x,
B's age = 2x,
A's age = 2x + 2.
X +2x+ 2x+2=27.
5x +2=27,
5x =25,
X=5.
B's Age= 2x.
2*5 = 10.
(7)
Bradley S said:
11 months ago
Based on a simplistic alternate method the answer is 9.
As follows.
A + 2 = B.
7 + 2 = 9 .
Then
2B = C
2 *9 = 18
Sums 9 + 18 = 27
which verifies that B = 9.
As follows.
A + 2 = B.
7 + 2 = 9 .
Then
2B = C
2 *9 = 18
Sums 9 + 18 = 27
which verifies that B = 9.
(6)
Sahas said:
6 years ago
a = two years more than b+2.
b = twice on c 2x.
Assume c = x.
b+2+2x+x.
Substitute b.
2x+2+2x+x=5x.
5x= 27-2.
x=5.
b = 2*5 = 10.
b = twice on c 2x.
Assume c = x.
b+2+2x+x.
Substitute b.
2x+2+2x+x=5x.
5x= 27-2.
x=5.
b = 2*5 = 10.
(3)
Tanishq said:
5 years ago
a = two years more than b+2.
b = twice on c 2x.
Assume c = x.
b+2+2x+x.
Substitute b.
2x+2+2x+x = 5x.
5x = 27-2.
x = 5.
b = 2*5 = 10.
b = twice on c 2x.
Assume c = x.
b+2+2x+x.
Substitute b.
2x+2+2x+x = 5x.
5x = 27-2.
x = 5.
b = 2*5 = 10.
(3)
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