Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 4)
4.
A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B?
Answer: Option
Explanation:
Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25
x = 5.
Hence, B's age = 2x = 10 years.
Discussion:
79 comments Page 2 of 8.
JANAKIRAM said:
5 years ago
A = B+2
B = 2C = >C=B/2
A + B + C = 27.
Substitute A & C values in above equation
B + 2 + B + B/2 = 27.
5B/2 = 25.
B = 10.
B = 2C = >C=B/2
A + B + C = 27.
Substitute A & C values in above equation
B + 2 + B + B/2 = 27.
5B/2 = 25.
B = 10.
(2)
Shan said:
1 decade ago
Hi,
let c year is x
then B is twice of C then, B=2x
Then A is 2 years older then B, therefore now B=2x,Then A=2+B, that is A=2+2x
Therefore sum up all the value:[(2+2x)for A,2x for B,x for C]
therefore 2+2x+2x+x=27
5x+2=27
5x=27-2
5x=25
x=25/5
x=5
now B is directly linked with C rather then A
Therefore B=2x
where x=5
2*5=10 that'z it my frnd
let c year is x
then B is twice of C then, B=2x
Then A is 2 years older then B, therefore now B=2x,Then A=2+B, that is A=2+2x
Therefore sum up all the value:[(2+2x)for A,2x for B,x for C]
therefore 2+2x+2x+x=27
5x+2=27
5x=27-2
5x=25
x=25/5
x=5
now B is directly linked with C rather then A
Therefore B=2x
where x=5
2*5=10 that'z it my frnd
(2)
Shrutika Gadhe said:
10 years ago
Let the age of B be 2x.
Ten the age of A will be 2x+2.
And the age of C will be x.
After that, x+2x+2+2x = 27.
= 3x+2x+2 = 27.
= 5x+2 = 27.
= 5x = 27-2.
= 5x = 25.
x = 25/5.
x = 5.
Therefore the age of B 2x = 2*5 = 10.
Ten the age of A will be 2x+2.
And the age of C will be x.
After that, x+2x+2+2x = 27.
= 3x+2x+2 = 27.
= 5x+2 = 27.
= 5x = 27-2.
= 5x = 25.
x = 25/5.
x = 5.
Therefore the age of B 2x = 2*5 = 10.
(1)
Nikunj said:
5 years ago
Simply, the solution is
(x+2) + x + 0.5x = 27.
x + x + 0.5x = 25.
x = 10.
(x+2) + x + 0.5x = 27.
x + x + 0.5x = 25.
x = 10.
(1)
Chandra hero said:
3 years ago
B - A = A - C.
B = 20/2.
= 10.
B = 20/2.
= 10.
(1)
SANJAY said:
8 years ago
Let,
Age of C is x years.
Then the age of B is 2x years.
And the age of A is 2x+2 years.
2x+2+2x+x = 27.
5x = 25.
Therefore x = 5.
Therefore the age of B is 2x = 2*5 = 10 years.
Age of C is x years.
Then the age of B is 2x years.
And the age of A is 2x+2 years.
2x+2+2x+x = 27.
5x = 25.
Therefore x = 5.
Therefore the age of B is 2x = 2*5 = 10 years.
(1)
Pavani said:
8 years ago
If we do option verification, option C(ans 9) is satisfying.
i.e. 11+9+7=27.
i.e. 11+9+7=27.
(1)
Prashant Singh said:
8 years ago
If, A is three times older than B, C is half the age of D, B is older than C. than what is the correct answer?
(a) A is older than D
(B) B is older than D
Please tell me with the explanation.
(a) A is older than D
(B) B is older than D
Please tell me with the explanation.
(1)
Shahid101 said:
9 years ago
Lets.
A=B+2.
From this we have B=A-2.
Then, B=2C.
We have C=B/2.
Add all these,
A + B + C = 27.
Put the values of A B and C.
B + 2 + A-2 + B/2 =27.
After solving, we will have.
3B + 2A = 54.
We want B's age, so put that value of B which is in terms of A.
3B+2 (B+2) =54.
Ultimately we have B=10.
Correct me if I'm mistaken anywhere, please.
A=B+2.
From this we have B=A-2.
Then, B=2C.
We have C=B/2.
Add all these,
A + B + C = 27.
Put the values of A B and C.
B + 2 + A-2 + B/2 =27.
After solving, we will have.
3B + 2A = 54.
We want B's age, so put that value of B which is in terms of A.
3B+2 (B+2) =54.
Ultimately we have B=10.
Correct me if I'm mistaken anywhere, please.
(1)
Ranadeep said:
1 decade ago
Let,
Age of C is x years.
Then age of B is 2x years.
And age of A is 2x+2 years.
2x+2+2x+x = 27.
5x = 25.
Therefore x = 5.
Therefore the age of B is 2x = 2*5 = 10 years.
Age of C is x years.
Then age of B is 2x years.
And age of A is 2x+2 years.
2x+2+2x+x = 27.
5x = 25.
Therefore x = 5.
Therefore the age of B is 2x = 2*5 = 10 years.
(1)
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