Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 4)
4.
A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B?
7
8
9
10
11
Answer: Option
Explanation:

Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.

(2x + 2) + 2x + x = 27

5x = 25

x = 5.

Hence, B's age = 2x = 10 years.

Discussion:
79 comments Page 4 of 8.

Sairam.b said:   9 years ago
Thank you @Kalai.

Sagar said:   9 years ago
According to me, the answer is 9.

Dhinu said:   9 years ago
Remember as "is" implies "=".

Saro said:   9 years ago
A = 2 + B,

B = 2C,

A + B + C = 27.

So, (2 + B) + B + B/2 = 27,

2B + B/2 = 25,

5B/2 = 25,

B = 10.

Sonam said:   9 years ago
Solve this. The three sibling in a family is Anu, Rita, Bunu. Rita age is four years older than Anu and Bunu is Two years older than Rita. The sum of their ages is 40. Bunu age is?

Shriram Nagorao Deshmukh said:   9 years ago
A = 2 + B.

B = 2C -> Eq 1.

A + B + C = 27 -> Eq 2.

Put value of A and B in 2,

2 + 2C + 2C + C = 27,
2C + 2C + C = 27 - 2,
2C + 2C + C= 25,
5C = 25,
C = 5,

Put C in eq 1,

B = 2 * 5,
B = 10.

Suraj said:   9 years ago
If b = x,
then,

a = 2 + x
c = 2 + 2 + x = 4 + x.

Then,
a + b + c = 27.
(2 + x) + x + (4 + x) = 27.
3x = 27 + 2 + 4.
x = 33/3.
x = 10.

Xyz abc said:   9 years ago
B = x, A = x+2, C = 1/2x.

Right?

Hayat said:   10 years ago
Let B=x.

Then according to 1st condition.

A=2+B (B=x).

So A=2+x.

2nd condition B=2C so C=B/2 (B=x).

C=x/2.

Add A, B and C.

A+B+C=27.

(2+x) + (2 (x/2) ) + (x/2) =27.

Simplify the equation.

5x+4=50.

X=10 (option D ans).

Shrutika Gadhe said:   10 years ago
Let the age of B be 2x.

Ten the age of A will be 2x+2.

And the age of C will be x.

After that, x+2x+2+2x = 27.

= 3x+2x+2 = 27.
= 5x+2 = 27.

= 5x = 27-2.
= 5x = 25.

x = 25/5.
x = 5.

Therefore the age of B 2x = 2*5 = 10.
(1)


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