Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 4)
4.
A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B?
Answer: Option
Explanation:
Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25
x = 5.
Hence, B's age = 2x = 10 years.
Discussion:
79 comments Page 6 of 8.
Maddy said:
1 decade ago
Hi guys! can anyone tell me how to consider "x" in these questions and father son type ques?
Vinitha said:
1 decade ago
Do you know any other methods to solve the sum friends?
Ranadeep said:
1 decade ago
Let,
Age of C is x years.
Then age of B is 2x years.
And age of A is 2x+2 years.
2x+2+2x+x = 27.
5x = 25.
Therefore x = 5.
Therefore the age of B is 2x = 2*5 = 10 years.
Age of C is x years.
Then age of B is 2x years.
And age of A is 2x+2 years.
2x+2+2x+x = 27.
5x = 25.
Therefore x = 5.
Therefore the age of B is 2x = 2*5 = 10 years.
(1)
Mourya said:
1 decade ago
B is twice of C so C is half of B so you have to replace c = x/2 you will get answer.
NEETA said:
1 decade ago
Why can't we take B=x? if answer is same when we assume any one out of A B C =x, answer will be wrong if we assume B=x
B=X
A=X+2
C=2X
Then A+B+C=27
X+2+X+2X=27
4X+2=27
4X=27-2
X=25/4
X=6.25
B=X
A=X+2
C=2X
Then A+B+C=27
X+2+X+2X=27
4X+2=27
4X=27-2
X=25/4
X=6.25
Shajil george said:
1 decade ago
Let the age of c is x
Given that the age of b is twice of c age so,
b is age is 2x
Similarly
a is two years grater than b is age, so,
a is 2x+x
From the Question
The sum of a,b,c is 27
Then,
2x+2+2x+x=27
5x+2=27
5x=27-2
5x=25
x=25/5
=5
So,the age of b is 2x,
The value of x is 5
So the age of bis 10.
Given that the age of b is twice of c age so,
b is age is 2x
Similarly
a is two years grater than b is age, so,
a is 2x+x
From the Question
The sum of a,b,c is 27
Then,
2x+2+2x+x=27
5x+2=27
5x=27-2
5x=25
x=25/5
=5
So,the age of b is 2x,
The value of x is 5
So the age of bis 10.
Rupinder said:
1 decade ago
A+B+C=27----------(1)
A=B+2-------------(2)
B=2C => C=B/2-----(3)
Put (3),(2) in (1)
=>(B+2)+B+(B/2)=27;
=> 2B+4+2B+B=54;
=> 5B=50-4;
=> B=10;
Hope it'll help you
A=B+2-------------(2)
B=2C => C=B/2-----(3)
Put (3),(2) in (1)
=>(B+2)+B+(B/2)=27;
=> 2B+4+2B+B=54;
=> 5B=50-4;
=> B=10;
Hope it'll help you
Kalai said:
1 decade ago
A is 2 years old than B ===> A= B+2
B is Twice as old than c ===> B=2C ==> C=B/2
A+B+C = 27
So we can write as below
A+B+C = 27
B+2+B+B/2 = 27
B+B+B/2=27-2
2B+B/2=25
(4B+B)/2=25
5B=50
B=10
B is Twice as old than c ===> B=2C ==> C=B/2
A+B+C = 27
So we can write as below
A+B+C = 27
B+2+B+B/2 = 27
B+B+B/2=27-2
2B+B/2=25
(4B+B)/2=25
5B=50
B=10
Geetha said:
1 decade ago
How u get x=18000 and y=6000?
How it come?
106/100
109/100
How it come?
106/100
109/100
Renu said:
1 decade ago
A+B+C=27
(B+2)+B+(B-2)=27
3B=27
B=9
(B+2)+B+(B-2)=27
3B=27
B=9
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