# Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 15)

15.

A bag contains 6 black and 8 white balls. One ball is drawn at random. What is the probability that the ball drawn is white?

Answer: Option

Explanation:

Let number of balls = (6 + 8) = 14.

Number of white balls = 8.

P (drawing a white ball) = | 8 | = | 4 | . |

14 | 7 |

Discussion:

29 comments Page 1 of 3.
Purva said:
2 years ago

By the complement rule.

P(W) = 1-P(B).

= 1 = 6/14 = 4/7.

P(W) = 1-P(B).

= 1 = 6/14 = 4/7.

(2)

Krishna said:
2 years ago

Let P(S) be probability of getting 1 ball from 14 balls,

P(S) = 14C1 = 14.

Let P(E) be probability of getting 1 white ball from 8 white balls,

P(E) = 8C1 = 8.

P(E)/P(S) = 8/14 = 4/7.

P(S) = 14C1 = 14.

Let P(E) be probability of getting 1 white ball from 8 white balls,

P(E) = 8C1 = 8.

P(E)/P(S) = 8/14 = 4/7.

(1)

Rahul said:
3 years ago

@Harshita.

Thank you.

Thank you.

Priya said:
5 years ago

@Vivek Bag1 contains 1/2red and bag 2 contains twice of Bag1 so 2*1/2and 1/4th of red balls in bag 2. So 2*1/2*1/4=1/4. Then 1/2+1/4=3/4.

Harshita said:
5 years ago

The total no of the ball is = 14.

The white ball is = 8.

so the probability of getting the white ball is= 8/14 = 4/7 this is the right answer.

The white ball is = 8.

so the probability of getting the white ball is= 8/14 = 4/7 this is the right answer.

(2)

Hemalatha said:
5 years ago

@Rajat.

The answer is 3.981.

The answer is 3.981.

Honey said:
5 years ago

Let's assume that bag 1 contains 10 balls of which half are red balls means.

Bag 1 = 5 red balls.. Bag 2 contains twice of bag 1 balls =(10* 2) 20 balls.1/4 of balls in bag 2 are red = 20/4 = 5 balls.

Therefore, red balls in bag 1 = red balls in bag 2.

Bag 1 = 5 red balls.. Bag 2 contains twice of bag 1 balls =(10* 2) 20 balls.1/4 of balls in bag 2 are red = 20/4 = 5 balls.

Therefore, red balls in bag 1 = red balls in bag 2.

Vivek said:
5 years ago

Half of the balls in bag 1 are red. Bag2 contains twice as many balls as are in bag 1 and one -fourth of all balls in bag 2 are red. Find the proportion of red balls in both the bags together?

Can anyone solve this?

Can anyone solve this?

Rajat said:
6 years ago

Two cards are drawn from a deck of 52 cards without replacement. What is the probability of getting both cards black or getting one card queen and the other one is king. What is the answer of this question? Please explain me.

Vamsi said:
6 years ago

Good explanations, thank you all.

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