Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 15)
15.
A bag contains 6 black and 8 white balls. One ball is drawn at random. What is the probability that the ball drawn is white?
Answer: Option
Explanation:
Let number of balls = (6 + 8) = 14.
Number of white balls = 8.
| P (drawing a white ball) = | 8 | = | 4 | . |
| 14 | 7 |
Discussion:
29 comments Page 1 of 3.
Anish said:
8 years ago
@Aastha.
Look this question, it is very easy. They have given us 6 black and 8 white balls. We should find the probability of white balls.
Total number of balls = 6 + 8 = 14.
Number of white balls = 8 (favorable outcome).
The probability of the white balls = favorable outcome\total outcome.
= 8\14.
= 4\7.
Look this question, it is very easy. They have given us 6 black and 8 white balls. We should find the probability of white balls.
Total number of balls = 6 + 8 = 14.
Number of white balls = 8 (favorable outcome).
The probability of the white balls = favorable outcome\total outcome.
= 8\14.
= 4\7.
Honey said:
5 years ago
Let's assume that bag 1 contains 10 balls of which half are red balls means.
Bag 1 = 5 red balls.. Bag 2 contains twice of bag 1 balls =(10* 2) 20 balls.1/4 of balls in bag 2 are red = 20/4 = 5 balls.
Therefore, red balls in bag 1 = red balls in bag 2.
Bag 1 = 5 red balls.. Bag 2 contains twice of bag 1 balls =(10* 2) 20 balls.1/4 of balls in bag 2 are red = 20/4 = 5 balls.
Therefore, red balls in bag 1 = red balls in bag 2.
Rajat said:
6 years ago
Two cards are drawn from a deck of 52 cards without replacement. What is the probability of getting both cards black or getting one card queen and the other one is king. What is the answer of this question? Please explain me.
Vivek said:
5 years ago
Half of the balls in bag 1 are red. Bag2 contains twice as many balls as are in bag 1 and one -fourth of all balls in bag 2 are red. Find the proportion of red balls in both the bags together?
Can anyone solve this?
Can anyone solve this?
Hassan said:
1 decade ago
C3 means the possible combinations of 3 balls from a group of 8 or 14.
We can take 3 balls from this group in variety of manners and in such situations we use combinations and hence C3.
We can take 3 balls from this group in variety of manners and in such situations we use combinations and hence C3.
Krishna said:
2 years ago
Let P(S) be probability of getting 1 ball from 14 balls,
P(S) = 14C1 = 14.
Let P(E) be probability of getting 1 white ball from 8 white balls,
P(E) = 8C1 = 8.
P(E)/P(S) = 8/14 = 4/7.
P(S) = 14C1 = 14.
Let P(E) be probability of getting 1 white ball from 8 white balls,
P(E) = 8C1 = 8.
P(E)/P(S) = 8/14 = 4/7.
(1)
Pranki said:
8 years ago
@Aastha,
You have to pick a ball from a bag containing 6 Black and 8 white balls. The ball you picked could be of any color. So the chance that it is white color is 8/14.
You have to pick a ball from a bag containing 6 Black and 8 white balls. The ball you picked could be of any color. So the chance that it is white color is 8/14.
RamGom said:
1 decade ago
Ex:
We can get 1 ball means total 14 balls 1 combination that means 14C1 = 14.
If 2 ball means total 14 balls 2 combination that means 14C2 = 14x13/2x1 = 91.
And so on.
We can get 1 ball means total 14 balls 1 combination that means 14C1 = 14.
If 2 ball means total 14 balls 2 combination that means 14C2 = 14x13/2x1 = 91.
And so on.
Neha said:
7 years ago
There are 600 boys in a hostel each plays either cricket or football or both if 75%plays cricket and 45% play football how many boys play both? Can anyone solve this?
Harshita said:
5 years ago
The total no of the ball is = 14.
The white ball is = 8.
so the probability of getting the white ball is= 8/14 = 4/7 this is the right answer.
The white ball is = 8.
so the probability of getting the white ball is= 8/14 = 4/7 this is the right answer.
(2)
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