Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 11)

Probability

11.

A card is drawn from a pack of 52 cards. The probability of getting a queen of club or a king of heart is:

Answer: Option

Explanation:

Here, n(S) = 52.

Let E = event of getting a queen of club or a king of heart.

Then, n(E) = 2.

P(E) =	n(E)	=	2	=	1	.
	n(S)		52		26

Discussion:

55 comments Page 4 of 6.

Pavan Mitra said: 1 decade ago

By or we mean either a king of heart or a queen of clubs, so p(king of heart)=1/52=p(queen of clubs) and n(e)=2, So p=2/52=1/26.

KHAN said: 1 decade ago

See actually only one queen is there in club and only one king in heart therefore it will be : 1C1+1C1=2.

2/52=1/26.

Amiya Acharya said: 7 years ago

In this it has been asking a queen of the club is 1C1,
A king of the heart is 1C1,
Probability = (1C1+1C1)/52C1.

(6)

Manish37 said: 5 years ago

You're right @Abhishek.

But we have to choose 1 out of 52 and same as king also. So the right answer is 1/26.

(3)

Anubhav said: 6 years ago

In cards 1 queen of the club and 1 king of heart and sum of the digits 1+1= 2.
The porbability= 2/56 = 1/26.

(6)

Sajna said: 1 decade ago

In question, the term used is 'or', then how the probability of event became 2. (i.e, n (E) =2) ?

Vani said: 9 years ago

For this question, I got the answer as 2/13. But how it is 1/26? I don't no please tell me.

Kasi said: 1 decade ago

Club and heart containes 26 cards, we have to drawn a card from 26 cards so ans is 1/26.

Premananda Sahoo said: 8 years ago

The probability of any two card is 2/52.

Why is the card name andcolour is specified?

Rajesh said: 1 decade ago

The correct answer is-
n(F)=1+1
n(T)=52c1
then,
P=n(E)/n(T)=2/52
=1/26

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