Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 11)
11.
A card is drawn from a pack of 52 cards. The probability of getting a queen of club or a king of heart is:
Answer: Option
Explanation:
Here, n(S) = 52.
Let E = event of getting a queen of club or a king of heart.
Then, n(E) = 2.
 P(E) = |
n(E) | = | 2 | = | 1 | . |
| n(S) | 52 | 26 |
Discussion:
55 comments Page 3 of 6.
Santhosh said:
3 months ago
There is one Queen of Clubs in a standard deck of 52 playing cards. Each suit has one Queen, and the club's suit has its own Queen card.
Which means club = clever.
Which means club = clever.
Rajesh said:
1 decade ago
But out of four club only one queen.So the probability of getting one queen=4/52.
In my opinion answer should be [B]=2/13
P(AUB)=P(A)+P(B)=4/52+4/52=8/52=8/52=2/13
In my opinion answer should be [B]=2/13
P(AUB)=P(A)+P(B)=4/52+4/52=8/52=8/52=2/13
Kannan said:
2 decades ago
(4C1 X 4C1)/52C1
what is the error in this method? Why cant I follow this method?
I know i'm wrong, but please clarify my doubt...
Thanking you..
what is the error in this method? Why cant I follow this method?
I know i'm wrong, but please clarify my doubt...
Thanking you..
Ananthasubramanian said:
7 years ago
The Probability would be 1/51. The question is from the whole pack of cards & not from only Hearts & clubs, Please clarify 1/26. Thanks,
Nishant sharma said:
9 years ago
@Kannan - Because we know that there is only 1 queen of club in 52 cards, here is no probability its definite so that's why we took 1+1.
MR.AB said:
8 years ago
Two cards are a dream at random from a pack of 52 cards. What is the probability that they are king and queen?
Can anyone answer it?
Can anyone answer it?
Oman kumar said:
9 years ago
Here you said, one queen or one king. So we have to consider either king or queen right? Then the anser will be 1/52. How it's 1/26?
RAVULA S NARAYANA said:
1 decade ago
WE HAVE ONLY 1 QUEEN IN A CLUB AND 1 KING IN HEART SO WE HAVE TWO
EVENTS ONLY
So,
P(E) = 1/52 + 1/52
= 2/52
= 1/26.
EVENTS ONLY
So,
P(E) = 1/52 + 1/52
= 2/52
= 1/26.
Suresh said:
7 years ago
In total ,there are 13 queen and 13 kings i.e .,n(S)= 26,
n(E)= 2C1 = 2 ( king or queen).
So n(P) = n(S)/n(S) = 2/26 = 1/13.
n(E)= 2C1 = 2 ( king or queen).
So n(P) = n(S)/n(S) = 2/26 = 1/13.
(2)
Shailesh khare said:
1 decade ago
Both event are independent.
Therefore problem of one event is 1/52 and other is 1/52.
P(e) = 1/52+1/52 = 1/26 is right answer.
Therefore problem of one event is 1/52 and other is 1/52.
P(e) = 1/52+1/52 = 1/26 is right answer.
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