# Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 4)

4.

What is the probability of getting a sum 9 from two throws of a dice?

Answer: Option

Explanation:

In two throws of a dice, *n*(S) = (6 x 6) = 36.

Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}.

P(E) = | n(E) |
= | 4 | = | 1 | . |

n(S) |
36 | 9 |

Discussion:

51 comments Page 1 of 6.
Laiba said:
2 years ago

As we know one dice has 6 sides(4 edges + 1frontside + 1backside = 6)

Possibilities of getting sum 9 are (6,3)(5,4)(4,5)(3,6) i.e 4 possibilities.

Because;

6+3 = 9

5+4 = 9

4+5 = 9

3+6 = 9.

Remember! The numbers you add should not exceed the 6 digit.

Solution for your question is @Dhaval.

4/6 * 6 * 6 = 4/216 or 1/54.

Hope,This Helps!

Possibilities of getting sum 9 are (6,3)(5,4)(4,5)(3,6) i.e 4 possibilities.

Because;

6+3 = 9

5+4 = 9

4+5 = 9

3+6 = 9.

Remember! The numbers you add should not exceed the 6 digit.

Solution for your question is @Dhaval.

4/6 * 6 * 6 = 4/216 or 1/54.

Hope,This Helps!

Qaisar wagay said:
2 years ago

Here how could you consider (5, 4) and (4, 5) two different events? Please explain.

Ankita said:
3 years ago

Why not taking the case {3,3}? Please explain me.

Nikolay said:
4 years ago

@Pooja Gm.

Dice does not have 8 surfaces it has only 6.

Dice does not have 8 surfaces it has only 6.

(1)

Surya said:
4 years ago

One dice have six faces so here we have two dices, so the formula is n2 (n Square). So 6*6 =36.

RRK said:
4 years ago

Is throwing a dice two times and throwing two dice together, same?

Please, anyone, clear me.

Please, anyone, clear me.

Arif said:
4 years ago

At first you draw sample space then you find pair which sum is 9, (1,1), (1,2),....... (5,4), (6,3),(3,6), (4,5).

Total pair 36 and sum of 9 pair is 4 them p(sum 9)= 4 ÷ 36 = 1/9.

Total pair 36 and sum of 9 pair is 4 them p(sum 9)= 4 ÷ 36 = 1/9.

(1)

Joshua said:
4 years ago

Because in a throw of two dices there is only 6x6, is the last the number won't Or should not exceed 6.

Swathi said:
5 years ago

Why we should not use the permutations here?like sum 9 can appear in either (6, 3) or (3, 6) , (5, 4) or (4, 5). Why we only choose the one possibility?

Pooja gm said:
5 years ago

Why we take this case only?

(3+6)

(4+5)

(5+4)

(6+3).

This also possible;

(7+2),

(1+8),

(2+7),

(8+1),

Please explain the reason.

(3+6)

(4+5)

(5+4)

(6+3).

This also possible;

(7+2),

(1+8),

(2+7),

(8+1),

Please explain the reason.

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