Aptitude - Probability - Discussion

As we know one dice has 6 sides(4 edges + 1frontside + 1backside = 6)
Possibilities of getting sum 9 are (6,3)(5,4)(4,5)(3,6) i.e 4 possibilities.
Because;
6+3 = 9
5+4 = 9
4+5 = 9
3+6 = 9.

Remember! The numbers you add should not exceed the 6 digit.

Solution for your question is @Dhaval.
4/6 * 6 * 6 = 4/216 or 1/54.
Hope,This Helps!

One dice means 6 faces.
Two dice means 6 * 6 = 36 faces.
Either,
(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)
(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)
(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)
(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)
(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)
(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)
Total = 36 outcomes.
So question ask that,
Sum =9.
So,
3 + 6 = 9 (3,6)
6 + 3 = 9 (6,3)
4 + 5 = 9 (4,5)
5 + 4 = 9 (5,4)
4 out comes.
p = num of outcomes/total outcomes.
p = 4/36 = 1/9.

Hope you understand this.

Here how could you consider (5, 4) and (4, 5) two different events? Please explain.

At first you draw sample space then you find pair which sum is 9, (1,1), (1,2),....... (5,4), (6,3),(3,6), (4,5).

Total pair 36 and sum of 9 pair is 4 them p(sum 9)= 4 ÷ 36 = 1/9.

(1/8) is also possible for the answer. Right?

@Pooja Gm.

Dice does not have 8 surfaces it has only 6.

Why not taking the case {3,3}? Please explain me.

One dice have six faces so here we have two dices, so the formula is n2 (n Square). So 6*6 =36.

Is throwing a dice two times and throwing two dice together, same?

Please, anyone, clear me.

Because in a throw of two dices there is only 6x6, is the last the number won't Or should not exceed 6.