Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 4)
4.
What is the probability of getting a sum 9 from two throws of a dice?
Answer: Option
Explanation:
In two throws of a dice, n(S) = (6 x 6) = 36.
Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}.
 P(E) = |
n(E) | = | 4 | = | 1 | . |
| n(S) | 36 | 9 |
Discussion:
52 comments Page 1 of 6.
Malasrvizhi said:
1 decade ago
How did get the sum element?
Rama said:
1 decade ago
How to select n(e) = 4.
VIAN said:
1 decade ago
@rama.
That is because the event of finding the sum 9 is 4.
That is because the event of finding the sum 9 is 4.
AZAM said:
1 decade ago
In two throws of a dice, n(S) = (6 x 6) = 36.
HOW IT DO
PLEASE EXPLAIN
HOW IT DO
PLEASE EXPLAIN
Krish said:
1 decade ago
How it could be n(s)= (6 x 6)
Srinivas said:
1 decade ago
n(s)=36
n(a)=[36][45][63][54]
p(a)=4/36=1/9
n(a)=[36][45][63][54]
p(a)=4/36=1/9
Sreejith said:
1 decade ago
@Azam
In both throughs, it can be any of 1,2,3...,6(6C1 ways of selection). So total number of outcomes = 6C1*6C1 = 36
More clearly, the elements of sample spaces are
{(1,1),(1,2),(1,3),....,(2,1),(2,2),.....(6,1),(6,2),....(6,6)}
Hope you got it.
In both throughs, it can be any of 1,2,3...,6(6C1 ways of selection). So total number of outcomes = 6C1*6C1 = 36
More clearly, the elements of sample spaces are
{(1,1),(1,2),(1,3),....,(2,1),(2,2),.....(6,1),(6,2),....(6,6)}
Hope you got it.
Harikannan said:
1 decade ago
How to find event that is (3, 4) (4, 5) (5, 4) (6, 3) please explain.
Syam said:
1 decade ago
{ (3, 6) , (4, 5) , (5, 4) , (6, 3) } is a case only.
We can get (6, 3) , (5, 4) , (3, 6) , (4, 5) also.
So answer is 8/38 = 2/9.
Am I correct ?
We can get (6, 3) , (5, 4) , (3, 6) , (4, 5) also.
So answer is 8/38 = 2/9.
Am I correct ?
Ankita said:
1 decade ago
How do we know that we have to pick up 6 * 6?
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