Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 4)
4.
What is the probability of getting a sum 9 from two throws of a dice?
1
6
1
8
1
9
1
12
Answer: Option
Explanation:

In two throws of a dice, n(S) = (6 x 6) = 36.

Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}.

P(E) = n(E) = 4 = 1 .
n(S) 36 9

Discussion:
52 comments Page 2 of 6.

Pooja gm said:   7 years ago
Why we take this case only?
(3+6)
(4+5)
(5+4)
(6+3).

This also possible;
(7+2),
(1+8),
(2+7),
(8+1),

Please explain the reason.
(1)

Prince said:   8 years ago
Why we take these cases only?

(3+6) = 9.
(4+5) = 9.
(5+4) = 9.
(6+3) = 9.

Neetu Sanghvi said:   9 years ago
I agree @Sree Tulasi.

Sarita said:   9 years ago
How can it be 6x6?

Two throws of a dice mean 6+6. Your answer can only be till 12, not 36.

Yallaling Dashavant said:   9 years ago
Sum 9 means (1,8)(2,7)(3,6)(4,5)(5,4)(6 3)(7,2).

Means 8/36 = 2/9.

Harini said:   9 years ago
How could n (S) be 36?

Shankar said:   9 years ago
Thanks for your solution @Sreejith.

B.lokesh said:   9 years ago
One dice means 6 faces.
Two dice means 6 * 6 = 36 faces.
Either,
(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)
(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)
(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)
(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)
(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)
(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)
Total = 36 outcomes.
So question ask that,
Sum =9.
So,
3 + 6 = 9 (3,6)
6 + 3 = 9 (6,3)
4 + 5 = 9 (4,5)
5 + 4 = 9 (5,4)
4 out comes.
p = num of outcomes/total outcomes.
p = 4/36 = 1/9.

Hope you understand this.
(6)

Umar said:   9 years ago
9 + 9 = 18,
=> 2/18 = 1/9.

Chethan said:   9 years ago
Why they took n(E)/n(S)? In some other problem, they took n(S)/n(E).


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