Aptitude - Pipes and Cistern - Discussion

Discussion Forum : Pipes and Cistern - General Questions (Q.No. 15)
15.
Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is:
10
12
14
16
Answer: Option
Explanation:

Part filled in 2 hours = 2 = 1
6 3

Remaining part = 1 - 1 = 2 .
3 3

(A + B)'s 7 hour's work = 2
3

(A + B)'s 1 hour's work = 2
21

C's 1 hour's work = { (A + B + C)'s 1 hour's work } - { (A + B)'s 1 hour's work }

   = 1 - 2 = 1
6 21 14

C alone can fill the tank in 14 hours.

Discussion:
44 comments Page 3 of 5.

Vickneswari said:   7 years ago
Why did you divide 42 by 3?

And how?

Deepa said:   8 years ago
1/A+1/B+1/C=1/6,
1/A+1/B=1/7.
1/6-1/7=1/42,
42/3=14.

Sugirtha said:   9 years ago
A pipe takes 9 mins to fill the tank. B takes 11.24 mins to fill the tank. C is a draining pipe. Three pipes are opened simultaneously after some time C is closed, A and B fills the remaining tank in 3.75 mins. How much Time C takes to empty the tank? Anyone please solve this.

Sahil sharma said:   1 decade ago
How 6 hrs are calculated here?

Dinesh said:   1 decade ago
A&B&C can fill a tank together in 6 hrs
but they worked together for 2 hrs only
so u hv to calculate the time finished in 2 hrs so
A&B&C=1/6
For two hrs =2/6=1/3

Sharvari said:   1 decade ago
How to calculate (A+B)in 7 hours ??

Nfl said:   1 decade ago
@Sharvari.

A+B+C = 2/6= 1/3 ..remaining part of cistern filled by A+B by 7 hours.

Remaining part 2/3 in 7 hours.. for exact 1 hour by A+B= 2/3*1/7=1/21.

Vishaka said:   1 decade ago
How to calculate (A+B) in 7 hours ?

Harshitha said:   1 decade ago
Can you explain the step (A+B) 's 1 hour work = 2/21.

Tamaghna said:   1 decade ago
What's the 1 hour calculation of (a+b+c)?


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