Aptitude - Pipes and Cistern - Discussion
Discussion Forum : Pipes and Cistern - General Questions (Q.No. 15)
15.
Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is:
Answer: Option
Explanation:
| Part filled in 2 hours = | 2 | = | 1 |
| 6 | 3 |
| Remaining part = |  |
1 - | 1 |  |
= | 2 | . |
| 3 | 3 |
 (A + B)'s 7 hour's work = |
2 |
| 3 |
| (A + B)'s 1 hour's work = | 2 |
| 21 |
C's 1 hour's work = { (A + B + C)'s 1 hour's work } - { (A + B)'s 1 hour's work }
| = | |
1 | - | 2 | |
= | 1 |
| 6 | 21 | 14 |
C alone can fill the tank in 14 hours.
Discussion:
44 comments Page 5 of 5.
Namrata said:
9 years ago
As we know x/a + x/b + x/c = x/6.
Write equation as;
(X/6) * 2 + (x/6 - x/c) * 7 = x.
After solving this equation you will get answer as 14.
Write equation as;
(X/6) * 2 + (x/6 - x/c) * 7 = x.
After solving this equation you will get answer as 14.
Sri vidhya said:
9 years ago
Why we need to calculate the final step for that one hour for A & B & C and A & B?
Hemanth said:
9 years ago
Hi, I am not getting this, please give me a proper explanation.
Shiny said:
9 years ago
A takes 9 mins to fill. B takes 11.24 mins to fill. C is draining pipe, three pipes are opened after sometime C alone closed, A and B takes 3.75 mins to fill the tank. How much C alone take to empty the filled tank? Can you please solve this.
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