Aptitude - Pipes and Cistern - Discussion
Discussion Forum : Pipes and Cistern - General Questions (Q.No. 3)
3.
A pump can fill a tank with water in 2 hours. Because of a leak, it took 2
hours to fill the tank. The leak can drain all the water of the tank in:
hours to fill the tank. The leak can drain all the water of the tank in:Answer: Option
Explanation:
| Work done by the leak in 1 hour = |  |
1 | - | 3 |  |
= | 1 | . |
| 2 | 7 | 14 |
Leak will empty the tank in 14 hrs.
Discussion:
90 comments Page 5 of 9.
Deepi said:
1 decade ago
A takes 2 hrs lets take as x
Leakage time lets y
2 1/3 hrs=7/3hrs
=> (x*y)/(y-x)=7/3
=> (2y)/(y-2)=7/3
=> 2y=(y-2)(7/3)
=> 2y=(7y/3)-14/3
=> -y/3=-14/3
=> y=14
Leakage time lets y
2 1/3 hrs=7/3hrs
=> (x*y)/(y-x)=7/3
=> (2y)/(y-2)=7/3
=> 2y=(y-2)(7/3)
=> 2y=(7y/3)-14/3
=> -y/3=-14/3
=> y=14
Govindarajan said:
1 decade ago
20 mins extra for 2 hour i.e. 120 mins.
120 mins is first tank.
140 mins is second tank.
120/x = 140/20.
140/20*120 = 840 mins.
1 hour = 60 mins.
14 hours = 14 hours.
120 mins is first tank.
140 mins is second tank.
120/x = 140/20.
140/20*120 = 840 mins.
1 hour = 60 mins.
14 hours = 14 hours.
Yamini Dhanasekar said:
7 years ago
@Jamsheed.
Always, we can consider total work be 1.
So
Hour ---- Work completed.
x ---- 1
3 ---- ?
By, cross multiplication,
3/X of the work.
Hope you understand.
Always, we can consider total work be 1.
So
Hour ---- Work completed.
x ---- 1
3 ---- ?
By, cross multiplication,
3/X of the work.
Hope you understand.
Saiprakash holi said:
9 years ago
Let A take 2hrs to fill.
B take 'x' hrs to empty the tank.
(A-B) per = 2 1/3hrs =7/3.
(A-B) per= Aper -Bper.
1/ (3/7) =1/2 - 1/x.
1/x = 1/2 - 7/3.
x = 14.
B take 'x' hrs to empty the tank.
(A-B) per = 2 1/3hrs =7/3.
(A-B) per= Aper -Bper.
1/ (3/7) =1/2 - 1/x.
1/x = 1/2 - 7/3.
x = 14.
Anuj said:
8 years ago
Without leakage a takes 2 hours with,
leakage 7/3 hour take lcm of 7/3 *3=7and 2*3=6.
lcm of 6 and 7=42 it takes more 1/3 hour so divide 42 by 3 =42/3 =14.
leakage 7/3 hour take lcm of 7/3 *3=7and 2*3=6.
lcm of 6 and 7=42 it takes more 1/3 hour so divide 42 by 3 =42/3 =14.
Rajeev said:
9 years ago
Here it is mentioned as 2 hrs for the tank and for leak tank time also given 2 hrs instead of 2hrs 20 min. SO I am also confused that how 3/7 comes?
SHUBHAM NALE said:
5 years ago
Let take a leak as an outlet named B.
The capacity of the tank is 14/3 litr.e
A=7/3 litre/hr and,
B=-2.
A+B=-1/3.
Therefore.
14/3 / -1/3 = 14.
The capacity of the tank is 14/3 litr.e
A=7/3 litre/hr and,
B=-2.
A+B=-1/3.
Therefore.
14/3 / -1/3 = 14.
Priya said:
1 decade ago
I had one doubt if suppose they are asking to find when the tank is filled due to its leakage means how to solve it? Please can anyone explain?
SAHID said:
8 years ago
First, it takes 120 min for leakage it lake (120+1/3*60=120+20)=140 min then LCM(120 and 140 it. It give 840min. 840/60 = 14hours.
Anjali tengli said:
8 years ago
Without leakage it takes 2 hrs.
In 1 hr it take 1/2.
With leakage, it takes 7/3
In 1 hr 1/7/3 I.e. 3/7.
1/2 - 3/7= 11/14.
In 1 hr it take 1/2.
With leakage, it takes 7/3
In 1 hr 1/7/3 I.e. 3/7.
1/2 - 3/7= 11/14.
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