Aptitude - Pipes and Cistern - Discussion
Discussion Forum : Pipes and Cistern - General Questions (Q.No. 3)
3.
A pump can fill a tank with water in 2 hours. Because of a leak, it took 2
hours to fill the tank. The leak can drain all the water of the tank in:
hours to fill the tank. The leak can drain all the water of the tank in:Answer: Option
Explanation:
| Work done by the leak in 1 hour = |  |
1 | - | 3 |  |
= | 1 | . |
| 2 | 7 | 14 |
Leak will empty the tank in 14 hrs.
Discussion:
90 comments Page 4 of 9.
Abhilash said:
1 decade ago
Actually tank could have filled in 2 hr.
Part will be 1/2.
Let the time taken by the leakage is y.
Therefore, part is 1/y.
3/7 = (1/2-1/y) here 3/7 is the total time taken to fill the tank (in parts).
1/y = ((7-6))/14.
y = 14.
Part will be 1/2.
Let the time taken by the leakage is y.
Therefore, part is 1/y.
3/7 = (1/2-1/y) here 3/7 is the total time taken to fill the tank (in parts).
1/y = ((7-6))/14.
y = 14.
Anjali said:
1 decade ago
A pump can fill a tank with water in 2 hours. Because of a leak, it took 2 hours to fill the tank. No where it is written that its taking 2.20 mints to fill while after leakage. Then why everyone taking (7/3). I am lost. Do help.
Narendra said:
10 years ago
For inlet it takes one hour for 1/2 part. For leakage, let's consider it takes 1 hour for 1/x parts.
For 2 hours and 20 minutes the tank will be filled as question says: (1/2-1/X)*7/3 = 1 (the full tank having 1 part).
For 2 hours and 20 minutes the tank will be filled as question says: (1/2-1/X)*7/3 = 1 (the full tank having 1 part).
Rajeev said:
1 year ago
We know that total time required to fill up a tank is xy/y-x(which includes the inlet and outlet).
Here this time is given by 7/3.
The value of y is 2. By solving this, we get x=14/13.
Correct me, If I am wrong.
Here this time is given by 7/3.
The value of y is 2. By solving this, we get x=14/13.
Correct me, If I am wrong.
(2)
Ashu said:
1 decade ago
@chakri
If you take 7/3 hrs to complete 1 job
Then, what length of job will you take to complete in 1 hour
( what you do here is...use reciprocal value when u shift the value)
that is
7/3=>1
1=>3/7
If you take 7/3 hrs to complete 1 job
Then, what length of job will you take to complete in 1 hour
( what you do here is...use reciprocal value when u shift the value)
that is
7/3=>1
1=>3/7
Kuldhoj Bamjan said:
5 years ago
The problem is exactly useful. But the tank when fulfill and quarter fill, there must be change the speed or press of water in the leak. So the water cannot throughout the same or regular behind to end.
Hari said:
7 years ago
Assume they are 2 different pipes.
So total units of water to be filled is lcm of 2 and 7/3 =42units.
The leak takes 1/3time extra than 1st pipe.
So work done by the leak is 1/3 * 42 = 14.
So total units of water to be filled is lcm of 2 and 7/3 =42units.
The leak takes 1/3time extra than 1st pipe.
So work done by the leak is 1/3 * 42 = 14.
(1)
Mouni said:
10 years ago
A cistern is normally filled in 8 hrs. But takes 2 hrs more to fill because of a leak in its bottom. If the cistern is full, the tank will empty it in?
Please tell me with explanation.
Please tell me with explanation.
Murali said:
8 years ago
A pipe can fill a tank in 3 hours. Because of the leak in the bottom, it is filled in 4 hours. If the tank is full, how much time will the leak take to empty it?
Can anyone solve it?
Can anyone solve it?
Sujitha said:
11 months ago
@Vivek Anand.
Your way of explanation is good but you have to take LCM for both numbers which is 1/2 - 3/7 = 7-2/14 = 5/14.
But you have taken 1/2-3/7 = 6-7 /14 =>this LCM is wrong.
Your way of explanation is good but you have to take LCM for both numbers which is 1/2 - 3/7 = 7-2/14 = 5/14.
But you have taken 1/2-3/7 = 6-7 /14 =>this LCM is wrong.
(5)
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