Aptitude - Pipes and Cistern - Discussion
Discussion Forum : Pipes and Cistern - General Questions (Q.No. 1)
1.
Three pipes A, B and C can fill a tank from empty to full in 30 minutes, 20 minutes, and 10 minutes respectively. When the tank is empty, all the three pipes are opened. A, B and C discharge chemical solutions P,Q and R respectively. What is the proportion of the solution R in the liquid in the tank after 3 minutes?
Answer: Option
Explanation:
| Part filled by (A + B + C) in 3 minutes = 3 |  |
1 | + | 1 | + | 1 |  |
= | |
3 x | 11 | |
= | 11 | . |
| 30 | 20 | 10 | 60 | 20 |
| Part filled by C in 3 minutes = | 3 | . |
| 10 |
 Required ratio = |
|
3 | x | 20 | |
= | 6 | . |
| 10 | 11 | 11 |
Discussion:
75 comments Page 3 of 8.
Anand said:
1 decade ago
Percentage filled by A in 3 minute = 100x3/30.....1.
Percentage filled by B in 3 minute = 100x3/20.....2.
Percentage filled by C in 3 minute = 100x3/10.....3.
= 3/(1+2).
Percentage filled by B in 3 minute = 100x3/20.....2.
Percentage filled by C in 3 minute = 100x3/10.....3.
= 3/(1+2).
Sashank singh said:
1 decade ago
A, B and C can fill a tank in 6 hrs. After 2 hrs C is stopped. Then A and B together fill the tank in 7 hrs.
How much C will take individully take to fill the tank?
How much C will take individully take to fill the tank?
Moon said:
8 years ago
Part filled by (A + B + C) in 3 minutes = 3 = 1 + 1 + 1.
3 x 11 = 11.
30 20 10 60 20
Part filled by C in 3 minutes = 3.
10
Required ratio = 3x20= 6.
10 11 11
3 x 11 = 11.
30 20 10 60 20
Part filled by C in 3 minutes = 3.
10
Required ratio = 3x20= 6.
10 11 11
Rohit said:
6 years ago
LCM of 20,30 and 60 are but ratio 3,2 and 1 and their lcm is 6 which is diveded as by 2,3,6 respectively. Now sum is 11 and after 3 minutes q {3} 3+3 =6 /11
MOHAMMED KHAN SABBIR said:
5 years ago
Solution:
A = 30.
B = 20.
C = 10.
LCM = 60.
A:B:C = 2:3:6.
REQUIRED TIME FOR (A+B+C) = 60/11,
REQUIRED TIME FOR C = 60/6 = 10,
RATIO = (6O/11)/10 = 6/11.
A = 30.
B = 20.
C = 10.
LCM = 60.
A:B:C = 2:3:6.
REQUIRED TIME FOR (A+B+C) = 60/11,
REQUIRED TIME FOR C = 60/6 = 10,
RATIO = (6O/11)/10 = 6/11.
(7)
Aman Kumar said:
5 years ago
According to me,
30, 20, 10 LCM 60 means per unit of each pipe is;
2, 3, 6 total unit = 11.
We can write this way also 60\11 *3\10 = 6\11.
30, 20, 10 LCM 60 means per unit of each pipe is;
2, 3, 6 total unit = 11.
We can write this way also 60\11 *3\10 = 6\11.
(11)
JISHNU said:
9 years ago
Regardless of the minutes the ratio will always the same,
i.e, the ratio is [1/10] / [(1/30) + (1/20) + (1/10)] = (1/10)/(11/60) = 6/11.
i.e, the ratio is [1/10] / [(1/30) + (1/20) + (1/10)] = (1/10)/(11/60) = 6/11.
Srinivasan said:
1 decade ago
1/30 + 1/20 + 1/10 = {(2*1)+(3*1)+(6*1)}/60
= 11/60
do L.C.m Now add this, we'ii got wht u wnt...
It's simple........
= 11/60
do L.C.m Now add this, we'ii got wht u wnt...
It's simple........
G.Nandhini said:
1 decade ago
Proportion of are in the tank = Amount of are filled by Tap C in 3 min/Total amount of P, Q, are filled by Taps A, B, C for 3 mins.
Archisha said:
9 years ago
@Drishti Anand.
In the end, we are doing (3/10) / (11/20).
Which is equal to (3/10) * (20/11)
That's why we take it in reciprocal.
In the end, we are doing (3/10) / (11/20).
Which is equal to (3/10) * (20/11)
That's why we take it in reciprocal.
(1)
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