Aptitude - Pipes and Cistern - Discussion
Discussion Forum : Pipes and Cistern - General Questions (Q.No. 1)
1.
Three pipes A, B and C can fill a tank from empty to full in 30 minutes, 20 minutes, and 10 minutes respectively. When the tank is empty, all the three pipes are opened. A, B and C discharge chemical solutions P,Q and R respectively. What is the proportion of the solution R in the liquid in the tank after 3 minutes?
Answer: Option
Explanation:
| Part filled by (A + B + C) in 3 minutes = 3 |  |
1 | + | 1 | + | 1 |  |
= | |
3 x | 11 | |
= | 11 | . |
| 30 | 20 | 10 | 60 | 20 |
| Part filled by C in 3 minutes = | 3 | . |
| 10 |
 Required ratio = |
|
3 | x | 20 | |
= | 6 | . |
| 10 | 11 | 11 |
Discussion:
75 comments Page 2 of 8.
KS said:
2 years ago
Lcm = 60.
It means the total tank capacity is 60 liters.
A done in one min = 60/30= 2lit,
B done in one min = 60/ 20= 3 lit,
C done in one min = 60/ 10 = 6 lit,
So, Total lit in one minute = 11 lit,
So, Total lit in three mints = 11 * 3 = 33 lit,
C done in three min = 6 * 3 = 18.
C' share is after three minutes = 18/33 = 6/11 ans.
It means the total tank capacity is 60 liters.
A done in one min = 60/30= 2lit,
B done in one min = 60/ 20= 3 lit,
C done in one min = 60/ 10 = 6 lit,
So, Total lit in one minute = 11 lit,
So, Total lit in three mints = 11 * 3 = 33 lit,
C done in three min = 6 * 3 = 18.
C' share is after three minutes = 18/33 = 6/11 ans.
(50)
Soumitra Malo said:
2 years ago
Lcm = 60.
It means the total tank capacity is 60 lit.
A done in one min = 60/30= 2lit,
B done in one min = 60/ 20= 3 lit,
C done in one min = 60/ 10 = 6 lit,
So, Total lit in one min = 11 lit,
So, Total lit in three mints = 11 * 3 = 33 lit,
C done in three min = 6 * 3 = 18.
C' share is after three minutes = 18/33 = 6/11 ans.
It means the total tank capacity is 60 lit.
A done in one min = 60/30= 2lit,
B done in one min = 60/ 20= 3 lit,
C done in one min = 60/ 10 = 6 lit,
So, Total lit in one min = 11 lit,
So, Total lit in three mints = 11 * 3 = 33 lit,
C done in three min = 6 * 3 = 18.
C' share is after three minutes = 18/33 = 6/11 ans.
(74)
Subu said:
3 years ago
Lcm = 60 .it means total tank capacity is 60 lit.
A done in one min = 60/30= 2lit,
B done in one min = 60/ 20= 3 lit,
C done in one min = 60/ 10 = 6 lit,
So Total lit in one min = 11 lit,
So Total lit in three mints = 11 * 3 = 33 lit,
C done in three min = 6 * 3 = 18.
C' share is after three mints = 18/33 = 6/11 ans.
A done in one min = 60/30= 2lit,
B done in one min = 60/ 20= 3 lit,
C done in one min = 60/ 10 = 6 lit,
So Total lit in one min = 11 lit,
So Total lit in three mints = 11 * 3 = 33 lit,
C done in three min = 6 * 3 = 18.
C' share is after three mints = 18/33 = 6/11 ans.
(76)
Mruthyunjaya bm said:
5 years ago
Filled by C in 3 minutes = 3/10.
Filled by (A + B + C) in 3 minutes = 3 ( 1/30+ 1/20 +1/10)= 3*11/60 = 11/20.
As they told A B C proportional to P Q R (R=C).
Required ratio = chemical solution R in tank/ total chemical solution in tank.
i.e. (3/10)/(11/20),
=(3/10)*(20/11),
= (3*20)/(10*11),
= 60/110,
= 6/11.
Filled by (A + B + C) in 3 minutes = 3 ( 1/30+ 1/20 +1/10)= 3*11/60 = 11/20.
As they told A B C proportional to P Q R (R=C).
Required ratio = chemical solution R in tank/ total chemical solution in tank.
i.e. (3/10)/(11/20),
=(3/10)*(20/11),
= (3*20)/(10*11),
= 60/110,
= 6/11.
(8)
Shailesh Vishwakarma said:
7 years ago
A = 30min fill 100%.
B = 20min fill 100%.
C = 10min fill 100%.
if 3 min filling done all together then,
A =3min fill 10%,
B =3min fill 15%,
C =3min fill 30%.
P =10%,
Q = 15%,
R = 30%.
Total = 55% total tank filled.
Proportion of soln R in total liquid,
=R/Total,
=30/55,
=6/11.
B = 20min fill 100%.
C = 10min fill 100%.
if 3 min filling done all together then,
A =3min fill 10%,
B =3min fill 15%,
C =3min fill 30%.
P =10%,
Q = 15%,
R = 30%.
Total = 55% total tank filled.
Proportion of soln R in total liquid,
=R/Total,
=30/55,
=6/11.
(1)
K ravikumar said:
8 years ago
A pipe can fill 10% in three minutes that is 100÷3 * 100=10% b can fill 15% in three minutes 100/20=5.
5*3minutes =15%.
Similarly, C can fill in three minutes 30% so in three minutes entire work is 55% so C proportion is30÷55 = 6÷11.
5*3minutes =15%.
Similarly, C can fill in three minutes 30% so in three minutes entire work is 55% so C proportion is30÷55 = 6÷11.
(1)
Ajay said:
1 decade ago
Part filled by C in 3 minutes = 3/10
Part filled by (A + B + C) in 3 minutes = 3 ( 1/30+ 1/20 +1/10)= 3*11/60 = 11/20
Required ratio = chemical soluttion R in tank/ total chemical solution in tank
i.e. 3/10/11/20
= 3*20/10*11
= 60/110
= 6/11
Part filled by (A + B + C) in 3 minutes = 3 ( 1/30+ 1/20 +1/10)= 3*11/60 = 11/20
Required ratio = chemical soluttion R in tank/ total chemical solution in tank
i.e. 3/10/11/20
= 3*20/10*11
= 60/110
= 6/11
APA said:
2 weeks ago
A in 1 min = 1/30.
B in 1 min = 1/20.
C in 1 min = 1/10.
1/30 + 1/20 + 1/10 => (2 + 3 + 6)/60 => 11/60.
Now, three pipes in 3 min = 3 * 11/60 => 11/20.
C share in 3 min = 3 * 1/10 => 3/10.
Required ratio = (3/10 * 20/11) => 6/11.
B in 1 min = 1/20.
C in 1 min = 1/10.
1/30 + 1/20 + 1/10 => (2 + 3 + 6)/60 => 11/60.
Now, three pipes in 3 min = 3 * 11/60 => 11/20.
C share in 3 min = 3 * 1/10 => 3/10.
Required ratio = (3/10 * 20/11) => 6/11.
(3)
Niranjan kumar said:
1 decade ago
A - 30 min.
B - 20 min.
C - 10 min.
Now take LCM (30,20,10) = 60.
So,
A - 60/30 = 2 LTR.
B - 3LTR.
C - 6 LTR.
So TOTAL 2+3+6 = 11 LTR.
So proportion of C is 6/11.
So Simple.
B - 20 min.
C - 10 min.
Now take LCM (30,20,10) = 60.
So,
A - 60/30 = 2 LTR.
B - 3LTR.
C - 6 LTR.
So TOTAL 2+3+6 = 11 LTR.
So proportion of C is 6/11.
So Simple.
DVJS said:
4 weeks ago
Total 60 unit. (LCM of 10 20 30).
A in 1 min = 2 units.
B in 1 min = 3 units.
C in 1 min = 6 units.
A + B + C = (6 + 3 + 2) = 11 units.
So, C's contribution is 6/11 units.
A in 1 min = 2 units.
B in 1 min = 3 units.
C in 1 min = 6 units.
A + B + C = (6 + 3 + 2) = 11 units.
So, C's contribution is 6/11 units.
(5)
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