Aptitude - Pipes and Cistern - Discussion
Discussion Forum : Pipes and Cistern - General Questions (Q.No. 1)
1.
Three pipes A, B and C can fill a tank from empty to full in 30 minutes, 20 minutes, and 10 minutes respectively. When the tank is empty, all the three pipes are opened. A, B and C discharge chemical solutions P,Q and R respectively. What is the proportion of the solution R in the liquid in the tank after 3 minutes?
Answer: Option
Explanation:
| Part filled by (A + B + C) in 3 minutes = 3 |  |
1 | + | 1 | + | 1 |  |
= | |
3 x | 11 | |
= | 11 | . |
| 30 | 20 | 10 | 60 | 20 |
| Part filled by C in 3 minutes = | 3 | . |
| 10 |
 Required ratio = |
|
3 | x | 20 | |
= | 6 | . |
| 10 | 11 | 11 |
Discussion:
75 comments Page 4 of 8.
Kiran said:
1 decade ago
@Lalitha
= 1/30+1/20+1/10
So L.C.M of 30,20,10=60
Then 1/30+1/20+1/10=2+3+6/60
=11/60
ok
= 1/30+1/20+1/10
So L.C.M of 30,20,10=60
Then 1/30+1/20+1/10=2+3+6/60
=11/60
ok
Saikat said:
1 year ago
Total 60 unit.
A = 1 minute 2 unit
B =1 min 3 unit
C =1 min 6 unit.
So, Total (6+3+2)=11 unit.
C contribution is 6/11 unit.
A = 1 minute 2 unit
B =1 min 3 unit
C =1 min 6 unit.
So, Total (6+3+2)=11 unit.
C contribution is 6/11 unit.
(53)
Akshay said:
1 decade ago
@Angle
When c works for 1 min its work done in 1 min = 1/10
so when it works for 3 min its contribution = 3/10
When c works for 1 min its work done in 1 min = 1/10
so when it works for 3 min its contribution = 3/10
Dine said:
1 decade ago
They asking after 3 min
so they given as a b c proportional to p q r .
so r is c for 3 min it 3/10.
so they given as a b c proportional to p q r .
so r is c for 3 min it 3/10.
Xyz said:
10 years ago
Please give some simple explanation. Please tell me how to calculate LCM? I forgot it.
Deepanshu Sharma said:
5 years ago
@Satya.
Initially, we calculate as per pipe and for total, we need to do reciprocal.
Initially, we calculate as per pipe and for total, we need to do reciprocal.
Nandeesh said:
4 years ago
3/30 + 3/20 + 3/10.
(6+9+18)/60 = 33/60 = 11/20,
(3/10)/11/20 = (3/10*20/11) = 6/11.
(6+9+18)/60 = 33/60 = 11/20,
(3/10)/11/20 = (3/10*20/11) = 6/11.
(14)
PRAKASH KUMAR said:
1 decade ago
Is there is any shortcut methods in understanding the pipes and cisterns problems?
Sujohn rayamajhi said:
10 years ago
Why C's filling is counted twice? Once in total and then individually.
Anitha said:
7 years ago
C spend max time 10 minutes.
So, 3/10 minutes.
(3/10)*(20/11).
6/11.
So, 3/10 minutes.
(3/10)*(20/11).
6/11.
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