Aptitude - Permutation and Combination - Discussion

Discussion Forum : Permutation and Combination - General Questions (Q.No. 8)
8.
In how many ways a committee, consisting of 5 men and 6 women can be formed from 8 men and 10 women?
266
5040
11760
86400
None of these
Answer: Option
Explanation:
Required number of ways = (8C5 x 10C6)
= (8C3 x 10C4)
= 8 x 7 x 6 x 10 x 9 x 8 x 7
3 x 2 x 1 4 x 3 x 2 x 1
= 11760.
Discussion:
61 comments Page 5 of 7.

Musa said:   1 decade ago
I don't understand the formula used. Can somebody explain it?

Rohini said:   1 decade ago
Why we have to convert nCr = nC (n-r) ?

Sunita said:   1 decade ago
Its for simplicity you can do it by solving first step also.

Priyadarshini said:   1 decade ago
nCr=nC(n-r) is used for simplification purpose.

We can also calculate it directly as nCr.

Answer will be same in both ways.

JOE said:   1 decade ago
Actually the formula for combination is nCr = nC(n-r).

Therefore 8C5 = 8C(8-5) = 8C3.
the answers will come the same , simply it will make the problem easier
If the combination e.g is 11C4 then = 11C(11-4) = 11C7 it will also come the same answers with 11C4...

Senorita said:   1 decade ago
As per my knowledge d calculation above shows only selection part. Aren't we suppose to calculate the number of ways it can b arranged into? in this case 11! ?

Satya said:   2 decades ago
I'm not getting the second step of solution.

How it became (8C5 x 10C6) to (8C3 x 10C4)?

Manu said:   1 decade ago
Yes, If you do it with (nCr = nC (n-r) ) then also we are getting the same answer. Please don't get confuse.

RockstR said:   1 decade ago
Why are we not multiplying with 11! ? these 5 men and 6 women can also be arranged within themselves. Right?

Shuhaib said:   1 decade ago
Another method.

In unit place we can fix only one number ie 5. Other place we can selected 6c2. So answer is 6c2*1.


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