Aptitude - Permutation and Combination - Discussion

Discussion Forum : Permutation and Combination - General Questions (Q.No. 8)
8.
In how many ways a committee, consisting of 5 men and 6 women can be formed from 8 men and 10 women?
266
5040
11760
86400
None of these
Answer: Option
Explanation:
Required number of ways = (8C5 x 10C6)
= (8C3 x 10C4)
= 8 x 7 x 6 x 10 x 9 x 8 x 7
3 x 2 x 1 4 x 3 x 2 x 1
= 11760.
Discussion:
61 comments Page 1 of 7.

Satya said:   2 decades ago
I'm not getting the second step of solution.

How it became (8C5 x 10C6) to (8C3 x 10C4)?

Arpita said:   2 decades ago
Can someone tell how the second step conversion happen?.

Farjana said:   1 decade ago
Actually the formula for combination is nCr = nC(n-r).

Therefore 8C5 = 8C(8-5) = 8C3.

Sundar said:   1 decade ago
Hi Farjana,

Thanks for your valuable information. Have a nice day!

Decom said:   1 decade ago
Does this assume that the men/women can be in any order or have to be allocated a position in the group. I felt this was a little ambiguous.

Saloni said:   1 decade ago
Why there is a * sign instead it should be +?

Nagarajan said:   1 decade ago
May anyone exlplain why that conversion is required,

nCr = nC(n-r).

but I know it is the formula..

Please explain conceptually.

Sathya said:   1 decade ago
Why we didn't use this (nCr = nC(n-r)) formula in the following questions ?

http://www.indiabix.com/aptitude/permutation-and-combination/discussion-688
http://www.indiabix.com/aptitude/permutation-and-combination/discussion-684

Please explain me !!!!

Deepu2543651 said:   1 decade ago
Why we getting wrong answer while we directly apply nCr formula?

Musa said:   1 decade ago
I don't understand the formula used. Can somebody explain it?


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