Aptitude - Permutation and Combination - Discussion
Discussion Forum : Permutation and Combination - General Questions (Q.No. 8)
8.
In how many ways a committee, consisting of 5 men and 6 women can be formed from 8 men and 10 women?
Answer: Option
Explanation:
| Required number of ways | = (8C5 x 10C6) | |||||||
| = (8C3 x 10C4) | ||||||||
|
||||||||
| = 11760. |
Discussion:
61 comments Page 1 of 7.
Maheen said:
5 years ago
It can also be calculated by simply calculating the combination of 8C5 men and 10C6 women. The answer would be 56 and 210, respectively.
And lastly, multiplying the combination of both men and women, which would be 11760. The second step which is n-r is quite confusing to some.
Simply use the formulae of combination and you'll get your answer.
And lastly, multiplying the combination of both men and women, which would be 11760. The second step which is n-r is quite confusing to some.
Simply use the formulae of combination and you'll get your answer.
(7)
Mohan said:
7 years ago
8C5 = (8*7*6*5*4)/(5*4*3*2*1).
= (8*7*6)/(3*2*1).
= 8C3.
10C6 = (10*9*8*7*6*5)/(6*5*4*3*2*1).
= (10*9*8*7)/(4*3*2*1),
= 10C4.
= (8*7*6)/(3*2*1).
= 8C3.
10C6 = (10*9*8*7*6*5)/(6*5*4*3*2*1).
= (10*9*8*7)/(4*3*2*1),
= 10C4.
(6)
Sayali said:
7 years ago
nCr=n!/r! (n-r)! =8C5=8! /5!* 3! = 56.
&
10C6=10! /6! *4! =210.
Therefore, 56*210 = 11760.
&
10C6=10! /6! *4! =210.
Therefore, 56*210 = 11760.
(4)
Siddhant B said:
6 years ago
The question says men and women, not men or women.
So when we see "and" we use * not +. If the question was men or women then the answer would have been 56+210. But in this case, its men and women so its multiplication i.e 56*210 = 11760.
So when we see "and" we use * not +. If the question was men or women then the answer would have been 56+210. But in this case, its men and women so its multiplication i.e 56*210 = 11760.
(3)
Reena said:
2 years ago
When considering the committee, why aren't we considering the mixture inside the committee as well inside 5 +6 = 11 persons?
(2)
Sunil said:
4 years ago
Why ncr = nc(n-r)? Please explain me.
(2)
Tsherin said:
6 years ago
@Sayali and @Diwakar.
We know the formula for Combination:
nCr= n!/(n-r)!r! as mentioned.
But why we aren't using r? Please explain.
We know the formula for Combination:
nCr= n!/(n-r)!r! as mentioned.
But why we aren't using r? Please explain.
(1)
Lalit said:
6 years ago
As per @Farjana said, but we didn't apply this formula for previous examples see example -1.
(1)
Rahul said:
7 years ago
But, this is the formula of permutation, so why we convert?
(1)
Prakash said:
7 years ago
Kindly anyone tells the difference between permutations and combinations.
(1)
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