Aptitude - Permutation and Combination - Discussion
Discussion Forum : Permutation and Combination - General Questions (Q.No. 8)
8.
In how many ways a committee, consisting of 5 men and 6 women can be formed from 8 men and 10 women?
Answer: Option
Explanation:
Required number of ways | = (8C5 x 10C6) | |||||||
= (8C3 x 10C4) | ||||||||
|
||||||||
= 11760. |
Discussion:
61 comments Page 4 of 7.
Sandeep Kumar Mallick said:
8 months ago
@Reena.
Why Internal Arrangements Are Not Considered:
Nature of a Committee:
A committee is typically a group of individuals where order doesn't matter.
For example:
If we select A, B, C, D, E as the 5 men, this is the same as selecting B, A, C, D, E, or any other arrangement of these names. The focus is only on who is in the group, not the sequence.
Focus on Selection, Not Order:
The task is to determine how many ways we can select 5 men and 6 women. Since their roles or hierarchy aren't specified, the internal order of people in the committee is irrelevant.
Combination Formula Used:
This ensures we don’t double-count the same group in different orders.
Key Point: The committee is just a collection of members, so the order in which they are chosen or arranged doesn't matter.
Why Internal Arrangements Are Not Considered:
Nature of a Committee:
A committee is typically a group of individuals where order doesn't matter.
For example:
If we select A, B, C, D, E as the 5 men, this is the same as selecting B, A, C, D, E, or any other arrangement of these names. The focus is only on who is in the group, not the sequence.
Focus on Selection, Not Order:
The task is to determine how many ways we can select 5 men and 6 women. Since their roles or hierarchy aren't specified, the internal order of people in the committee is irrelevant.
Combination Formula Used:
This ensures we don’t double-count the same group in different orders.
Key Point: The committee is just a collection of members, so the order in which they are chosen or arranged doesn't matter.
Diwakar said:
1 decade ago
Formula: n!/r!(n-r)!
8C5 = 8!/5!(8-5) which is 6*7*8/1*2*3 = 56
10C6 = 10!/6!(10-6)! which is 7*8*9*10/1*2*3*4 = 210
Therefore: 56*210 = 11760
8C5 = 8!/5!(8-5) which is 6*7*8/1*2*3 = 56
10C6 = 10!/6!(10-6)! which is 7*8*9*10/1*2*3*4 = 210
Therefore: 56*210 = 11760
Arpita said:
2 decades ago
Can someone tell how the second step conversion happen?.
Farjana said:
1 decade ago
Actually the formula for combination is nCr = nC(n-r).
Therefore 8C5 = 8C(8-5) = 8C3.
Therefore 8C5 = 8C(8-5) = 8C3.
Sundar said:
1 decade ago
Hi Farjana,
Thanks for your valuable information. Have a nice day!
Thanks for your valuable information. Have a nice day!
Decom said:
1 decade ago
Does this assume that the men/women can be in any order or have to be allocated a position in the group. I felt this was a little ambiguous.
Saloni said:
1 decade ago
Why there is a * sign instead it should be +?
Nagarajan said:
1 decade ago
May anyone exlplain why that conversion is required,
nCr = nC(n-r).
but I know it is the formula..
Please explain conceptually.
nCr = nC(n-r).
but I know it is the formula..
Please explain conceptually.
Sathya said:
1 decade ago
Why we didn't use this (nCr = nC(n-r)) formula in the following questions ?
http://www.indiabix.com/aptitude/permutation-and-combination/discussion-688
http://www.indiabix.com/aptitude/permutation-and-combination/discussion-684
Please explain me !!!!
http://www.indiabix.com/aptitude/permutation-and-combination/discussion-688
http://www.indiabix.com/aptitude/permutation-and-combination/discussion-684
Please explain me !!!!
Deepu2543651 said:
1 decade ago
Why we getting wrong answer while we directly apply nCr formula?
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