Aptitude - Permutation and Combination - Discussion

Discussion Forum : Permutation and Combination - General Questions (Q.No. 8)
8.
In how many ways a committee, consisting of 5 men and 6 women can be formed from 8 men and 10 women?
266
5040
11760
86400
None of these
Answer: Option
Explanation:
Required number of ways = (8C5 x 10C6)
= (8C3 x 10C4)
= 8 x 7 x 6 x 10 x 9 x 8 x 7
3 x 2 x 1 4 x 3 x 2 x 1
= 11760.
Discussion:
61 comments Page 3 of 7.

Decom said:   1 decade ago
Does this assume that the men/women can be in any order or have to be allocated a position in the group. I felt this was a little ambiguous.

Vishesh bakshi said:   1 decade ago
Am always confused whether to multiply or add in between this two cases. How to determine it correctly can any one help me out on this?

Tsherin said:   5 years ago
@Sayali and @Diwakar.

We know the formula for Combination:
nCr= n!/(n-r)!r! as mentioned.
But why we aren't using r? Please explain.
(1)

Nagarajan said:   1 decade ago
May anyone exlplain why that conversion is required,

nCr = nC(n-r).

but I know it is the formula..

Please explain conceptually.

Mohan said:   6 years ago
8C5 = (8*7*6*5*4)/(5*4*3*2*1).
= (8*7*6)/(3*2*1).
= 8C3.

10C6 = (10*9*8*7*6*5)/(6*5*4*3*2*1).
= (10*9*8*7)/(4*3*2*1),
= 10C4.
(5)

Priyadarshini said:   1 decade ago
nCr=nC(n-r) is used for simplification purpose.

We can also calculate it directly as nCr.

Answer will be same in both ways.

Reena said:   1 year ago
When considering the committee, why aren't we considering the mixture inside the committee as well inside 5 +6 = 11 persons?
(2)

Nishat Parwez said:   1 decade ago
The correct formula for the mentioned question is n!/r!( n-r)!..

This makes the concept clear. Totally agree with @Diwakar.

Flair said:   1 decade ago
In this question don't give importance to arrangements. Like ABC=ACB=BAC they are same. Take this example with person.

Karthika said:   10 years ago
Why we are applying the ncr=n-r formula in the second step?

What is the purpose of using where we should we use this?


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