Aptitude - Permutation and Combination - Discussion
Discussion Forum : Permutation and Combination - General Questions (Q.No. 8)
8.
In how many ways a committee, consisting of 5 men and 6 women can be formed from 8 men and 10 women?
Answer: Option
Explanation:
| Required number of ways | = (8C5 x 10C6) | |||||||
| = (8C3 x 10C4) | ||||||||
|
||||||||
| = 11760. |
Discussion:
61 comments Page 2 of 7.
Farjana said:
2 decades ago
Actually the formula for combination is nCr = nC(n-r).
Therefore 8C5 = 8C(8-5) = 8C3.
Therefore 8C5 = 8C(8-5) = 8C3.
Siva said:
1 decade ago
Different arrangement of digits in a number gives different numbers, but arrangement doesn't alter the composition of a committee. So no need to calculate no.of arrangements. All arrangements give the same committee.
Gayudhaya said:
8 years ago
In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there?
By using above formula just explain it.
By using above formula just explain it.
Akash said:
9 years ago
Apply permutation formula when the order in which you place the object doesn't matter.
Permutation formula is : nPr = n! / (n-r)! * r! .
This is what is simply done here.
Permutation formula is : nPr = n! / (n-r)! * r! .
This is what is simply done here.
Vimala said:
1 decade ago
No need to multiply with 11! because they did not ask for the arrangement of the person. We need to concentrate only on the selection of person for the committee.
Senorita said:
1 decade ago
As per my knowledge d calculation above shows only selection part. Aren't we suppose to calculate the number of ways it can b arranged into? in this case 11! ?
Rishu.R said:
9 years ago
Why the second step conversion is needed? Is it necessary?
How do I predict the 2nd step conversion from the question?
Anyone, please help me. In detail.
How do I predict the 2nd step conversion from the question?
Anyone, please help me. In detail.
Younisali.syed said:
1 decade ago
I agree with this answer but when you see question no: 4 in that he selected and then arranged in this problem he only selected.
Any one tell me why so?
Any one tell me why so?
Diwakar said:
1 decade ago
Formula: n!/r!(n-r)!
8C5 = 8!/5!(8-5) which is 6*7*8/1*2*3 = 56
10C6 = 10!/6!(10-6)! which is 7*8*9*10/1*2*3*4 = 210
Therefore: 56*210 = 11760
8C5 = 8!/5!(8-5) which is 6*7*8/1*2*3 = 56
10C6 = 10!/6!(10-6)! which is 7*8*9*10/1*2*3*4 = 210
Therefore: 56*210 = 11760
Poonam said:
1 decade ago
Do not use the formula which does not exist for actual solution. That formula is for permutation which you given. Please explain in another way.
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