Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Answer: Option
Explanation:
Let their marks be (x + 9) and x.
| Then, x + 9 = | 56 | (x + 9 + x) |
| 100 |
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Discussion:
170 comments Page 7 of 17.
2ku said:
10 years ago
Dear @Kavi,
Here we assume that two students mark, one is secured than other in 9 marks.
So let 1st student is x.
2nd student is x+9 [2nd student is secured 9 marks than 1st].
Here we assume that two students mark, one is secured than other in 9 marks.
So let 1st student is x.
2nd student is x+9 [2nd student is secured 9 marks than 1st].
Nagajothi said:
1 year ago
Obtained mark % = 56.
Total mark %= 100.
Remaining % = 100 - 56 = 44%.
Difference % = 56-44 = 12%.
Then the difference mark 9.
So,
12 % = 9.
56% = x.
56*9/12 = 42.
42-9 = 33.
Total mark %= 100.
Remaining % = 100 - 56 = 44%.
Difference % = 56-44 = 12%.
Then the difference mark 9.
So,
12 % = 9.
56% = x.
56*9/12 = 42.
42-9 = 33.
(266)
Jayendra Malviya said:
2 years ago
Obtained mark% = 56 and Total mark %= 100.
Remaining % = 100 - 56 = 44%.
Difference % = 56-44 = 12%.
Then the difference mark 9.
So,
12 %=9.
56% =x.
56*9/12 =42.
42-9 = 33.
Remaining % = 100 - 56 = 44%.
Difference % = 56-44 = 12%.
Then the difference mark 9.
So,
12 %=9.
56% =x.
56*9/12 =42.
42-9 = 33.
(67)
Shubham thakur said:
9 years ago
It's very simple.
If 1student got 56% that means other got 44%.
56 - 44 = 12%.
Fr 12%~9 is there,
So, for 100% ~99.
Only pair which satisfies it is 39 & 30.
That it.
If 1student got 56% that means other got 44%.
56 - 44 = 12%.
Fr 12%~9 is there,
So, for 100% ~99.
Only pair which satisfies it is 39 & 30.
That it.
AVINASH KUMAR said:
2 years ago
A and B is there;
A + B = 100.
A = 56,B = 44,A - B = 12.
12%U = 9
12/100U = 9
3/25U = 9
3U = 9
1U = 3
A = 56% = 56/100,14/25U
A = 14U = 14 * 3 = 42
B = 11U = 11 * 3 = 33.
A + B = 100.
A = 56,B = 44,A - B = 12.
12%U = 9
12/100U = 9
3/25U = 9
3U = 9
1U = 3
A = 56% = 56/100,14/25U
A = 14U = 14 * 3 = 42
B = 11U = 11 * 3 = 33.
(37)
Mazher said:
10 years ago
@Tukuna Behera.
Why did we take the 25 to the R.H.S, that's the only step I did not understand, help please, or any one, why did we take the 25 to the Right Hand Side?
Why did we take the 25 to the R.H.S, that's the only step I did not understand, help please, or any one, why did we take the 25 to the Right Hand Side?
AlikaRai said:
8 years ago
I need help for this question. Kindly help me.
If the money is devalued by 4% find the% increase in money that will have to spent to buy a particular article.
If the money is devalued by 4% find the% increase in money that will have to spent to buy a particular article.
(1)
Md Attaullah said:
6 years ago
As per my method, the Solution is;
Gap in marks= 9.
Gap in percentage= 12%,
1st student marks = 56% = 56/12 * 9 = 42.
2nd student marks = 44% = 44/12 * 9 = 33.
Gap in marks= 9.
Gap in percentage= 12%,
1st student marks = 56% = 56/12 * 9 = 42.
2nd student marks = 44% = 44/12 * 9 = 33.
(1)
SANJAY said:
5 years ago
@All.
Simply, the solution is;
56 % and balance is 44, Right!
56/100 = 9,
56 - 44 / 100 = 9,
It will give you 75.
THEN,
56/100 X 75 = 42.
44/100 X 75 = 33.
Simply, the solution is;
56 % and balance is 44, Right!
56/100 = 9,
56 - 44 / 100 = 9,
It will give you 75.
THEN,
56/100 X 75 = 42.
44/100 X 75 = 33.
Suren said:
1 decade ago
Its very simple.
What is the % difference 12% mark difference 9 if 12% = 9; 56%=?
56*9/12 = 42 which is highest mark.
So 42-9 = 33.
Answer is 42, 33.
What is the % difference 12% mark difference 9 if 12% = 9; 56%=?
56*9/12 = 42 which is highest mark.
So 42-9 = 33.
Answer is 42, 33.
(1)
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