Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Answer: Option
Explanation:
Let their marks be (x + 9) and x.
| Then, x + 9 = | 56 | (x + 9 + x) |
| 100 |
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Discussion:
173 comments Page 5 of 18.
Krishnaa Kumari said:
2 months ago
Total marks = 100%.
X = 56%.
Y = 100-56.
= 44%.
Now the difference marks between X and Y.
= (56-44)%,
= 12%.
Now,
12% = 9,
1% = 9÷12,
56%= 9÷12 × 56,
= 42.
Next;
Y = 44%.
12% = 9.
1% = 9÷12,
44%= 9÷12 × 44,
= 33.
X = 56%.
Y = 100-56.
= 44%.
Now the difference marks between X and Y.
= (56-44)%,
= 12%.
Now,
12% = 9,
1% = 9÷12,
56%= 9÷12 × 56,
= 42.
Next;
Y = 44%.
12% = 9.
1% = 9÷12,
44%= 9÷12 × 44,
= 33.
(40)
Pawan said:
5 years ago
Answer = C.
1st students marks percentage = 56%,
2nd percentage= 100-56 = 44%,
Difference between marks = 9,
Difference between percentage=56-44 = 12%.
9 = 12% ->1 = 0.75 ->100 = 75(total marks).
56% = 0.75X56 = 42 ,44% = 0.75X44 = 33.
1st students marks percentage = 56%,
2nd percentage= 100-56 = 44%,
Difference between marks = 9,
Difference between percentage=56-44 = 12%.
9 = 12% ->1 = 0.75 ->100 = 75(total marks).
56% = 0.75X56 = 42 ,44% = 0.75X44 = 33.
(3)
Shrikant sir said:
1 decade ago
Just observe the question, you will find.
We assume total of both marks is 100 %.
1) 100-56 = 44.
2) 56-44 = 12.
3) It means 12% = 9 marks.
Than 44% = ?
You will get 33 marks.
4) Same way.
12% = 9 marks.
56% = ?
You will get 42 marks.
We assume total of both marks is 100 %.
1) 100-56 = 44.
2) 56-44 = 12.
3) It means 12% = 9 marks.
Than 44% = ?
You will get 33 marks.
4) Same way.
12% = 9 marks.
56% = ?
You will get 42 marks.
Sailu said:
6 years ago
Let student 1 = x.
2nd student secured 9marks more = (x+9).
This marks = 56%(total sum marks).
x+9 = 56/100(x+x+9)
100(x+9) = 56(2x+9)
100x+900 = 112x+504
900-504 = 112x-100x
396 = 12x
x = 396/12=33.
x = 33.
x+9 = 33+9 = 42.
(33, 42).
2nd student secured 9marks more = (x+9).
This marks = 56%(total sum marks).
x+9 = 56/100(x+x+9)
100(x+9) = 56(2x+9)
100x+900 = 112x+504
900-504 = 112x-100x
396 = 12x
x = 396/12=33.
x = 33.
x+9 = 33+9 = 42.
(33, 42).
Arshad said:
10 years ago
Try by Back Solving Method:
Lets try c: 42, 33 so it means total marks are : 42 + 33 = 75 Marks.
Let's try to find out 56 % from marks given in option C.
42 * 100/75 = 56 %
33 * 100/75 = 44 %.
So option C is the correct answer .
Lets try c: 42, 33 so it means total marks are : 42 + 33 = 75 Marks.
Let's try to find out 56 % from marks given in option C.
42 * 100/75 = 56 %
33 * 100/75 = 44 %.
So option C is the correct answer .
Anusha said:
1 decade ago
Solution: Let 1st person marks = x.
2nd person marks = x-9.
From question 1st person marks is 56% of sum of their marks.
x = 56/100(x+x-9).
x = 56/100(2x-9).
x = (56*2x)/100 - (56*9)/100.
x((56*20/100)-1) = (56*9)/100.
x = 42.
2nd person marks = x-9.
From question 1st person marks is 56% of sum of their marks.
x = 56/100(x+x-9).
x = 56/100(2x-9).
x = (56*2x)/100 - (56*9)/100.
x((56*20/100)-1) = (56*9)/100.
x = 42.
Vijay Kumar said:
9 months ago
Total marks = 100%
Obtained marks"×" = 56%
"Y" = 44%.
Here difference is = 12%(it means 9)
So each 1% = 0.75.
10% = 7.5 {100% = 75; 50% = 37.5; 6% = 4.50}
So 56%= 42{ 37.5 + 4.5}.
44% = 33{37.5 - 4.5}.
Obtained marks"×" = 56%
"Y" = 44%.
Here difference is = 12%(it means 9)
So each 1% = 0.75.
10% = 7.5 {100% = 75; 50% = 37.5; 6% = 4.50}
So 56%= 42{ 37.5 + 4.5}.
44% = 33{37.5 - 4.5}.
(32)
Rahul said:
1 decade ago
This is how I understood :
x = y+9.
x = 0.56(x+y).
x-y = 9.
x-0.56x-0.56y = 0.
0.44x-0.56y = 0.
x = (0.56/0.44)y.
x = (56/44)y.
(56/44)y - (44/44)y = 9.
(12/44)y = 9.
y = 9*44/12.
y = 3/4*44=3*11=33.
y = 33.
x = 33+9.
x = 42.
x = y+9.
x = 0.56(x+y).
x-y = 9.
x-0.56x-0.56y = 0.
0.44x-0.56y = 0.
x = (0.56/0.44)y.
x = (56/44)y.
(56/44)y - (44/44)y = 9.
(12/44)y = 9.
y = 9*44/12.
y = 3/4*44=3*11=33.
y = 33.
x = 33+9.
x = 42.
Hemant singh said:
1 decade ago
By question let first scoted x marks
then 2nd x+9
sum of ther marks {x+x+9}
not by ques the student who ha s scored x+9 marks = su m of marks of both students ie x+9=2x+9 of 56%
solve it now
then 2nd x+9
sum of ther marks {x+x+9}
not by ques the student who ha s scored x+9 marks = su m of marks of both students ie x+9=2x+9 of 56%
solve it now
Vino said:
1 decade ago
No confusion. Listen.
Assume total marks will be 100,
One student=x+9.
Another=x.
So,
For 100 he scored 56, so what marks for them so (x+9+x).
56/100* (x+9+x).
Now x+9 is student 1: So equate,
x+9 = 56/100* (x+9+x).
Assume total marks will be 100,
One student=x+9.
Another=x.
So,
For 100 he scored 56, so what marks for them so (x+9+x).
56/100* (x+9+x).
Now x+9 is student 1: So equate,
x+9 = 56/100* (x+9+x).
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