Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Answer: Option
Explanation:
Let their marks be (x + 9) and x.
| Then, x + 9 = | 56 | (x + 9 + x) |
| 100 |
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Discussion:
170 comments Page 4 of 17.
Jeeva said:
4 years ago
@Vel.
Two students x and y were appear then one get more than 9marks from the other so we take that one member as y as an assumption so y =x+9.
Here we have x and x+9 as two members. Then that x+9 's mark is 56%of sum of their marks. Hence we take (x+9) = 56% (x+ (x+9) ) = option c.
Two students x and y were appear then one get more than 9marks from the other so we take that one member as y as an assumption so y =x+9.
Here we have x and x+9 as two members. Then that x+9 's mark is 56%of sum of their marks. Hence we take (x+9) = 56% (x+ (x+9) ) = option c.
Swathi krishna said:
5 years ago
Given,
One of them secured 9 Mark's more than other.
And one person got 56%, the second person got 100-56=44.
Difference 56 - 44 = 12, So 12% is 9 Mark's.
12------------>9Mark's
56------------>?
56 * 9/12=42.
One person got 42 Mark's.
Another person got 42 - 9 = 33marks.
One of them secured 9 Mark's more than other.
And one person got 56%, the second person got 100-56=44.
Difference 56 - 44 = 12, So 12% is 9 Mark's.
12------------>9Mark's
56------------>?
56 * 9/12=42.
One person got 42 Mark's.
Another person got 42 - 9 = 33marks.
(3)
Vel7 said:
7 years ago
Take option c. 42, 33.
Then 42+33=75 so, 75= 100%.
7.5=10%.
0.75=1%.
We calulate 56% 1%= 0.75.
56%=0.75*56= 42
Difference 9. So 42-9=33.
Then 42+33=75 so, 75= 100%.
7.5=10%.
0.75=1%.
We calulate 56% 1%= 0.75.
56%=0.75*56= 42
Difference 9. So 42-9=33.
Sonu said:
8 years ago
A family consumes 25 kg rice and 9 kg wheat per month spends Rs. 350. The price of rice is 20% of the price of the wheat. If the price of wheat is increased by 20% then, find the % reduction in consumption of rice, if it has the same amount to spend.
Can anyone answer it?
Can anyone answer it?
Umang gandhi said:
9 years ago
Let two student a&b.
a scores 9 marks more than b and have 56%.
a = 56%.
b = 100-56 = 44%,
56% = 9 + 44%,
12% = 9.
Let total marks be x.
12%X = 9,
(12/100) * x = 9,
x = 75.
Sum of both a and b = 75.
We check option which satisfies above condition = 42, 33.
a scores 9 marks more than b and have 56%.
a = 56%.
b = 100-56 = 44%,
56% = 9 + 44%,
12% = 9.
Let total marks be x.
12%X = 9,
(12/100) * x = 9,
x = 75.
Sum of both a and b = 75.
We check option which satisfies above condition = 42, 33.
Swaminathan Vembu said:
1 decade ago
If I simplify the given statement and assemble it numerically what do I have ?
A. 39 = 56/100 * 69 => Not True.
B. 41 = 56/100 * 73 => Not True.
C. 42 = 56/100 * 75 => True.
D. 43 = 56/100 * 77 => Not True.
Therefore the correct answer is C.
A. 39 = 56/100 * 69 => Not True.
B. 41 = 56/100 * 73 => Not True.
C. 42 = 56/100 * 75 => True.
D. 43 = 56/100 * 77 => Not True.
Therefore the correct answer is C.
Girish P said:
7 years ago
Easiest way to solve this is as follows:
The total percentage of marks is 56%,
so divide 56 by 2,
You get 33, 1%=6 marks, the student has scored 9 marks more so,
33+9=42, the other student marks will be 9 marks less so simple,
42-9=33.
ANSWER=42 & 33.
The total percentage of marks is 56%,
so divide 56 by 2,
You get 33, 1%=6 marks, the student has scored 9 marks more so,
33+9=42, the other student marks will be 9 marks less so simple,
42-9=33.
ANSWER=42 & 33.
Megha said:
9 years ago
In an exam, 5%of the application were found ineligible &85% of the eligible candidates belongs to general category. If 4275 eligible candidates belonged to other categories, then how much candidates applied for the exam?
Please answer this question.
Please answer this question.
Aniket said:
1 decade ago
I need help on following question:
A candidate who gets 50% of total marks gets 100 marks more than the pass marks. Another candidate who gets 70% of the first candidates marks failed by 50 marks. How much percent a student needs to pass the exam?
A candidate who gets 50% of total marks gets 100 marks more than the pass marks. Another candidate who gets 70% of the first candidates marks failed by 50 marks. How much percent a student needs to pass the exam?
Pawan said:
4 years ago
Answer = C.
1st students marks percentage = 56%,
2nd percentage= 100-56 = 44%,
Difference between marks = 9,
Difference between percentage=56-44 = 12%.
9 = 12% ->1 = 0.75 ->100 = 75(total marks).
56% = 0.75X56 = 42 ,44% = 0.75X44 = 33.
1st students marks percentage = 56%,
2nd percentage= 100-56 = 44%,
Difference between marks = 9,
Difference between percentage=56-44 = 12%.
9 = 12% ->1 = 0.75 ->100 = 75(total marks).
56% = 0.75X56 = 42 ,44% = 0.75X44 = 33.
(3)
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