Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Answer: Option
Explanation:
Let their marks be (x + 9) and x.
| Then, x + 9 = | 56 | (x + 9 + x) |
| 100 |
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Discussion:
170 comments Page 16 of 17.
Shakthi said:
2 years ago
Let one student obtain x marks.
So, another obtained x+9 marks.
According to the question;
X+9 = 56/100'- (2x+9).
By cross multiplying.
3x = 99.
x = 33.
So, one obtained 33 and another obtained 33 + 9 = 42 as x+9.
So, another obtained x+9 marks.
According to the question;
X+9 = 56/100'- (2x+9).
By cross multiplying.
3x = 99.
x = 33.
So, one obtained 33 and another obtained 33 + 9 = 42 as x+9.
(31)
AVINASH KUMAR said:
2 years ago
A and B is there;
A + B = 100.
A = 56,B = 44,A - B = 12.
12%U = 9
12/100U = 9
3/25U = 9
3U = 9
1U = 3
A = 56% = 56/100,14/25U
A = 14U = 14 * 3 = 42
B = 11U = 11 * 3 = 33.
A + B = 100.
A = 56,B = 44,A - B = 12.
12%U = 9
12/100U = 9
3/25U = 9
3U = 9
1U = 3
A = 56% = 56/100,14/25U
A = 14U = 14 * 3 = 42
B = 11U = 11 * 3 = 33.
(37)
Moli said:
2 years ago
Total =100
F= 56%
S = ?.
So,
X = 100 - 56 = 44.
44 - 9 = 33.
F= 56%
S = ?.
So,
X = 100 - 56 = 44.
44 - 9 = 33.
(97)
Naveen Thonpunoori said:
2 years ago
Let's say X, and Y are students.
We can say Y got 44% of the total marks since X got 56%.
Percentage difference b/w X, Y is 56%- 44% = 12%.
X got 9 marks more than Y, So 9 marks are equal to 12%.
So, 1% of marks equal to, 9/12 = 0.75,
X marks are, 0.75 * 56 = 42.
Y marks are, 0.75 * 44 = 33.
We can say Y got 44% of the total marks since X got 56%.
Percentage difference b/w X, Y is 56%- 44% = 12%.
X got 9 marks more than Y, So 9 marks are equal to 12%.
So, 1% of marks equal to, 9/12 = 0.75,
X marks are, 0.75 * 56 = 42.
Y marks are, 0.75 * 44 = 33.
(62)
Santhiya said:
2 years ago
Total = 100.
F = 56%,
Therefore;
X = 100 - 56 = 44.
44 - 9 = X = 33.
F = 56%,
Therefore;
X = 100 - 56 = 44.
44 - 9 = X = 33.
(91)
Jayendra Malviya said:
2 years ago
Obtained mark% = 56 and Total mark %= 100.
Remaining % = 100 - 56 = 44%.
Difference % = 56-44 = 12%.
Then the difference mark 9.
So,
12 %=9.
56% =x.
56*9/12 =42.
42-9 = 33.
Remaining % = 100 - 56 = 44%.
Difference % = 56-44 = 12%.
Then the difference mark 9.
So,
12 %=9.
56% =x.
56*9/12 =42.
42-9 = 33.
(67)
Shahid Afridi said:
2 years ago
@All
Here, some people doing the wrong calculation 44-9=35 not 33. Please correct it.
Here, some people doing the wrong calculation 44-9=35 not 33. Please correct it.
(150)
Parvathi said:
2 years ago
Let total marks be =100.
F =56%.
Therefore,
X = 100-56 = 44,
44-9 = 33,
33+9 = 42.
F =56%.
Therefore,
X = 100-56 = 44,
44-9 = 33,
33+9 = 42.
(358)
Nagajothi said:
1 year ago
Obtained mark % = 56.
Total mark %= 100.
Remaining % = 100 - 56 = 44%.
Difference % = 56-44 = 12%.
Then the difference mark 9.
So,
12 % = 9.
56% = x.
56*9/12 = 42.
42-9 = 33.
Total mark %= 100.
Remaining % = 100 - 56 = 44%.
Difference % = 56-44 = 12%.
Then the difference mark 9.
So,
12 % = 9.
56% = x.
56*9/12 = 42.
42-9 = 33.
(266)
Anke Lakshmi said:
1 year ago
Let the marks obtained by the students be a and b:
Let a = b + 9 -------->1
a = (56/100) * (a+b) ---------> 2.
From equation 1, equation 2 can be written as;
b + 9 = (0.56) * (b + 9 + b),
b + 9 = (0.56)(2b + 9).
b + 9 = 1.12b + 5.04
9 - 5.04 = 1.12b - b.
3.96 = 0.12b,
b = 3.96/0.12,
b = 33.
Then, a=b+9
a=33+9
a=42
Therefore, marks scored by a and b are 42 and 33.
Let a = b + 9 -------->1
a = (56/100) * (a+b) ---------> 2.
From equation 1, equation 2 can be written as;
b + 9 = (0.56) * (b + 9 + b),
b + 9 = (0.56)(2b + 9).
b + 9 = 1.12b + 5.04
9 - 5.04 = 1.12b - b.
3.96 = 0.12b,
b = 3.96/0.12,
b = 33.
Then, a=b+9
a=33+9
a=42
Therefore, marks scored by a and b are 42 and 33.
(19)
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