Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Answer: Option
Explanation:
Let their marks be (x + 9) and x.
| Then, x + 9 = | 56 | (x + 9 + x) |
| 100 |
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Discussion:
170 comments Page 15 of 17.
Soham Garai said:
4 years ago
Let one student obtain x marks.
So, another obtained x+9 marks.
According to question.
X+9 = 56/100'- (2x+9).
By cross multiplying.
3x = 99.
x = 33.
So, one obtained 33 and another obtained 33 + 9 = 42 as x+9.
So, another obtained x+9 marks.
According to question.
X+9 = 56/100'- (2x+9).
By cross multiplying.
3x = 99.
x = 33.
So, one obtained 33 and another obtained 33 + 9 = 42 as x+9.
(4)
SOHAM GARAI said:
4 years ago
As one got X marks another X+9 so, the sum of both is 2x+9.
(4)
Rahul jha said:
4 years ago
Total 100%.
A have 56%.
i.e B = 100%-56% = 44%.
A have 9 mark more than B,
i.e A - B=9.
56% - 44%=9,
12% = 9,
4% = 3.
A = 56% / 4% = 14%.
14 * 3 = 42.
B = 44 %/4%
B = 11 * 3 = 33.
so, A = 42, B = 33.
A have 56%.
i.e B = 100%-56% = 44%.
A have 9 mark more than B,
i.e A - B=9.
56% - 44%=9,
12% = 9,
4% = 3.
A = 56% / 4% = 14%.
14 * 3 = 42.
B = 44 %/4%
B = 11 * 3 = 33.
so, A = 42, B = 33.
(13)
Rohit said:
4 years ago
Thank you for explaining @Rahul.
(3)
Aarti said:
3 years ago
Difference of the both students marks:
56% - 44% = 12%.
Difference is = 9
12% = 9
1% = 9/12
100% = 9*100/12 = 75.
Total marks = 75.
56% of total marks = 75*56/100 = 42.
42-9 = 33.
56% - 44% = 12%.
Difference is = 9
12% = 9
1% = 9/12
100% = 9*100/12 = 75.
Total marks = 75.
56% of total marks = 75*56/100 = 42.
42-9 = 33.
(94)
Dr.Mahaveer said:
3 years ago
@All.
Hello.
Simply, the solution is;
A = x+9,
B = x,
x+9 = 56%(x+x+9),
x+9 = 56/100(2x+9),
x = 33,
A = 33 + 9 = 42.
B = 33.
Hello.
Simply, the solution is;
A = x+9,
B = x,
x+9 = 56%(x+x+9),
x+9 = 56/100(2x+9),
x = 33,
A = 33 + 9 = 42.
B = 33.
(39)
Chernet said:
3 years ago
Thanks all for giving an excellent explanation.
(9)
Arjun said:
3 years ago
Why we Equalize 56/100 (2x+9) into x+9? can anyone please explain this?
(16)
Ritesh Rawal said:
3 years ago
Your explanation is simple & clear. Thank you very much @Neelu.
(20)
Suresh said:
3 years ago
Total mark% = 56.
Then the remaining percentage= 100 - 56 = 44%.
Difference percentage = 56-44 = 12%.
Then the difference mark= 9.
So, 12 percentage = 9 then what percent = 56% = 42.
42-9 = 33.
Then the remaining percentage= 100 - 56 = 44%.
Difference percentage = 56-44 = 12%.
Then the difference mark= 9.
So, 12 percentage = 9 then what percent = 56% = 42.
42-9 = 33.
(273)
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