Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Answer: Option
Explanation:
Let their marks be (x + 9) and x.
| Then, x + 9 = | 56 | (x + 9 + x) |
| 100 |
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Discussion:
170 comments Page 13 of 17.
Krishna said:
1 decade ago
@uttam
How it can be 56%-44%=9%?
Can you explain it?
How it can be 56%-44%=9%?
Can you explain it?
(1)
Babajan said:
9 years ago
Which formula of percentage are used in this question?
Aravind said:
1 decade ago
Why we put equate here between x+9 = 56/100* (x+9+x).
Deepikaravikumar said:
8 months ago
Still, I can't understand this. Please explain to me.
(25)
Sunil said:
9 years ago
What calculation do for this 25(x + 9) = 14(2x + 9)?
Bismah hanif said:
8 years ago
How? Please explain in detail. @Asif Husain Jafri.
Balaganesh said:
4 years ago
@Pawan.
From the QN, Sum of their mark % is 56%.
From the QN, Sum of their mark % is 56%.
Gaurav said:
5 years ago
@Geetha.
It comes 25/14 when you divide 56/100.
It comes 25/14 when you divide 56/100.
Rohan said:
7 years ago
@Hiren Savalia.
Can you elaborate your method?
Can you elaborate your method?
Chernet said:
3 years ago
Thanks all for giving an excellent explanation.
(9)
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