Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Answer: Option
Explanation:
Let their marks be (x + 9) and x.
| Then, x + 9 = | 56 | (x + 9 + x) |
| 100 |
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Discussion:
173 comments Page 12 of 18.
Moli said:
2 years ago
Total =100
F= 56%
S = ?.
So,
X = 100 - 56 = 44.
44 - 9 = 33.
F= 56%
S = ?.
So,
X = 100 - 56 = 44.
44 - 9 = 33.
(97)
Ritesh Rawal said:
3 years ago
Your explanation is simple & clear. Thank you very much @Neelu.
(20)
Karthikeyan said:
9 years ago
Can you please explain why we keep in x + 9 on the left side?
ISHITA said:
9 years ago
I can not understand the question. Please someone explain me.
Ntb said:
5 years ago
which formula did we use in this? Anyone explain me, please.
Santanu said:
9 years ago
56% - 44% = 9.
100% = 75.
Which total makes 75. That's it.
100% = 75.
Which total makes 75. That's it.
Sushmitha said:
8 years ago
25(x+9) = 14(2x+9) how its came?
Please explain this step.
Please explain this step.
SOHAM GARAI said:
4 years ago
As one got X marks another X+9 so, the sum of both is 2x+9.
(4)
Radhika said:
1 decade ago
56-44/100=9
12/100=9
=75
now
56/100*75=42
44/100*75=33
:)
12/100=9
=75
now
56/100*75=42
44/100*75=33
:)
(2)
Vel said:
1 decade ago
Ok why equal sign assigned b/w x+9 and 56/100 (x+9+x) ?
(1)
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