Aptitude - Percentage - Discussion

Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
39, 30
41, 32
42, 33
43, 34
Answer: Option
Explanation:

Let their marks be (x + 9) and x.

Then, x + 9 = 56 (x + 9 + x)
100

25(x + 9) = 14(2x + 9)

3x = 99

x = 33

So, their marks are 42 and 33.

Discussion:
170 comments Page 11 of 17.

Arjun said:   3 years ago
Why we Equalize 56/100 (2x+9) into x+9? can anyone please explain this?
(16)

SandipWaghmare said:   10 years ago
@Sawant.

= 30/100*x = 180*100/30.

x = (180*100/30)100/30.

x = 270.

Santhiya said:   2 years ago
Total = 100.
F = 56%,

Therefore;
X = 100 - 56 = 44.
44 - 9 = X = 33.
(91)

Geetha said:   5 years ago
Where does this 25 and 14 in equation come? Please explain about it.

Harsha said:   5 years ago
Why we make x+x+9 their? I am not getting that, Anyone explain me.
(1)

Anu said:   1 decade ago
=> 25(x + 9) = 14(2x + 9).
=> 3x = 99.

How it became this?

Ravi said:   10 years ago
Option method is too easy and fastest way to solve this question.

Archana Gaikwad said:   9 years ago
56% - 44 = 9.

But please explain 100% = 75.

& How 25 come?

Moli said:   2 years ago
Total =100
F= 56%
S = ?.

So,
X = 100 - 56 = 44.
44 - 9 = 33.
(97)

Ritesh Rawal said:   3 years ago
Your explanation is simple & clear. Thank you very much @Neelu.
(20)


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