Aptitude - Percentage - Discussion

Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
39, 30
41, 32
42, 33
43, 34
Answer: Option
Explanation:

Let their marks be (x + 9) and x.

Then, x + 9 = 56 (x + 9 + x)
100

25(x + 9) = 14(2x + 9)

3x = 99

x = 33

So, their marks are 42 and 33.

Discussion:
173 comments Page 10 of 18.

Asif husain jafri said:   8 years ago
First, sum all the option and find its 56%.
in option 42+33=75.
75 of 56% =42.
42-9=33.

Prakhar Maheshwari said:   7 years ago
Answer is C.

I have directly used option to get the answer.

So, 42/75*100 =56%; (42+33 =75).

Aman Tomar said:   8 years ago
Hello Guys
Simple method.

A=x+9,
B=x,
x+9=56%(x+x+9),
x+9=56/100(2x+9),
x=33,
A=33+9=42.
B=33.

Chahat Mishra tcet said:   9 months ago
VERY EASY:

Let total marks be = 100.
F =56%.
Therefore,
X = 100-56 = 44,
44-9 = 33,
33+9 = 42.
(545)

Suraj said:   1 decade ago
25X+225=28X+126
28X=25X+225-126
28X=25X+99
28X-25X=99
3X=99
X=99/3
X=33
Ans:x=33; x+9=33+9=42.

Ashwin said:   6 years ago
@Sarwat

30%of number 180,
30/100*y=180.
y=600.
15%of3(number) =? .
15/100*3(600) =2700.

Dhiren said:   4 years ago
Simple way using ratio.

56 : 44.
i.e 14:11.
33 is divisible by 11 so the answer is C.
(17)

Shahid Afridi said:   2 years ago
@All

Here, some people doing the wrong calculation 44-9=35 not 33. Please correct it.
(152)

Parvathi said:   2 years ago
Let total marks be =100.
F =56%.

Therefore,
X = 100-56 = 44,
44-9 = 33,
33+9 = 42.
(360)

Viral said:   1 decade ago
@Radhika
How can u write this eq.
56-44/100=9
means why u put 9 to the R.H.S?


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