Aptitude - Percentage - Discussion

Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
39, 30
41, 32
42, 33
43, 34
Answer: Option
Explanation:

Let their marks be (x + 9) and x.

Then, x + 9 = 56 (x + 9 + x)
100

25(x + 9) = 14(2x + 9)

3x = 99

x = 33

So, their marks are 42 and 33.

Discussion:
170 comments Page 14 of 17.

Maryam said:   1 decade ago
y u write (x+9+x)on the other side of equalto

Gyanajyoti said:   8 years ago
Bdw why (x+9+w) became multiple with 56/100?

Roopsingh said:   7 years ago
How come 56/100? Please explain in detail.

Anirudh razdan said:   9 years ago
Why do we equate it to x + 9? Why not x?

Nikhila said:   8 years ago
Where you get 25 and 14? Please tell me.

Jajjo said:   8 years ago
How you can take 25 at lhs and 14 rhs?

Hariharan E said:   8 years ago
Please explain how to get the answer?

Mohit said:   1 decade ago
How did you that 25, 225, 28, 126 ?

Anthea said:   1 decade ago
@Ashok

Y did u divide 56/100 by 4?

Anthea said:   1 decade ago
@Ashok

Y did u divide 56/100 by 4?


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