Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Answer: Option
Explanation:
Let their marks be (x + 9) and x.
| Then, x + 9 = | 56 | (x + 9 + x) |
| 100 |
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Discussion:
173 comments Page 14 of 18.
Rohan said:
7 years ago
@Hiren Savalia.
Can you elaborate your method?
Can you elaborate your method?
Chernet said:
4 years ago
Thanks all for giving an excellent explanation.
(9)
Maryam said:
1 decade ago
y u write (x+9+x)on the other side of equalto
Gyanajyoti said:
8 years ago
Bdw why (x+9+w) became multiple with 56/100?
Roopsingh said:
7 years ago
How come 56/100? Please explain in detail.
Anirudh razdan said:
9 years ago
Why do we equate it to x + 9? Why not x?
Nikhila said:
8 years ago
Where you get 25 and 14? Please tell me.
Jajjo said:
8 years ago
How you can take 25 at lhs and 14 rhs?
Preetika said:
4 weeks ago
How 25 has come? Please explain to me.
(2)
Hariharan E said:
8 years ago
Please explain how to get the answer?
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