Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 12)
12.
Two tailors X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
Answer: Option
Explanation:
Let the sum paid to Y per week be Rs. z.
Then, z + 120% of z = 550.
 z + |
120 | z = 550 |
| 100 |
| |
11 | z = 550 |
| 5 |
| z = |
 |
550 x 5 |  = 250. |
| 11 |
Discussion:
82 comments Page 7 of 9.
Vinoth said:
2 decades ago
I didn't understand this sum how will come to y=100. Then how will come to 11/5 can you explain for me ?
Obama keeps selling creditsvia IMF said:
2 decades ago
Bravo ramesh!
Priyanka said:
9 years ago
Thanks for your solution @Girish.
Ramesh said:
2 decades ago
Let amount paid to Y = 100
then amount paid to x= 120% of 100 = 120
total paid i.e., x + y = 100 + 120 = 220
if total paid is 220, amount paid to y=100
if total paid is 550, how much is paid to 'Y"
100/220*550=250
then amount paid to x= 120% of 100 = 120
total paid i.e., x + y = 100 + 120 = 220
if total paid is 220, amount paid to y=100
if total paid is 550, how much is paid to 'Y"
100/220*550=250
Sudarshan G said:
8 years ago
@Ramesh.
Thanks for explaining the solution.
Thanks for explaining the solution.
Ram's power said:
8 years ago
@All.
Actually, given X+Y=550,
X=120%=120/100=6/5,
Then 6/5+Y=550,
Denominator 5 then,
(6+5y)=550,
11Y=550*5=2750,
Y=2750/11=250.
Actually, given X+Y=550,
X=120%=120/100=6/5,
Then 6/5+Y=550,
Denominator 5 then,
(6+5y)=550,
11Y=550*5=2750,
Y=2750/11=250.
Balaji said:
8 years ago
Good explanation @Ramesh.
Suresh said:
8 years ago
Thanks @Ashok.
GOWTHAM said:
9 years ago
Total X+Y=550rs,
Y=550-X,
By questions:
X=(120/100)*(550-X)---> eq(1)
By solving equations(1).
X=300rs.
Y=250rs.
Y=550-X,
By questions:
X=(120/100)*(550-X)---> eq(1)
By solving equations(1).
X=300rs.
Y=250rs.
Gopi said:
9 years ago
Excellent, Thanks @Girish.
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