Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 12)
12.
Two tailors X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
Answer: Option
Explanation:
Let the sum paid to Y per week be Rs. z.
Then, z + 120% of z = 550.
 z + |
120 | z = 550 |
| 100 |
| |
11 | z = 550 |
| 5 |
| z = |
 |
550 x 5 |  = 250. |
| 11 |
Discussion:
78 comments Page 1 of 8.
Ramesh said:
1 decade ago
Let amount paid to Y = 100
then amount paid to x= 120% of 100 = 120
total paid i.e., x + y = 100 + 120 = 220
if total paid is 220, amount paid to y=100
if total paid is 550, how much is paid to 'Y"
100/220*550=250
then amount paid to x= 120% of 100 = 120
total paid i.e., x + y = 100 + 120 = 220
if total paid is 220, amount paid to y=100
if total paid is 550, how much is paid to 'Y"
100/220*550=250
Obama keeps selling creditsvia IMF said:
1 decade ago
Bravo ramesh!
Vinoth said:
1 decade ago
I didn't understand this sum how will come to y=100. Then how will come to 11/5 can you explain for me ?
Amrutha said:
1 decade ago
@Vinoth.
This type of problems can be easily solved in the method posted by ramesh here we have to assume that y=100 and calculate the problem.
This type of problems can be easily solved in the method posted by ramesh here we have to assume that y=100 and calculate the problem.
Mini said:
1 decade ago
Combined salary of X and Y is 550
:. X+Y=550
120% of Y+Y =550(as X is paid 120 percent of the sum paid to Y,
120/100Y+Y=550 so substitute X for 120%ofY)
12/10Y+Y=550
12Y+10Y=5500 (by taking l.c.m)
22Y=5500
Y=5500/22
Y=500/2
Y=250
:. X+Y=550
120% of Y+Y =550(as X is paid 120 percent of the sum paid to Y,
120/100Y+Y=550 so substitute X for 120%ofY)
12/10Y+Y=550
12Y+10Y=5500 (by taking l.c.m)
22Y=5500
Y=5500/22
Y=500/2
Y=250
Divya said:
1 decade ago
Thank you mini.
Anitha said:
1 decade ago
Thanks Ramesh.
Lalit said:
1 decade ago
Given,
X=120/100 Y.
X=6/5 Y.
Now X+Y=550.
And 6/5 Y+Y=550.
11Y/5=550.
Y/5=50.
Y=250.
Hope you would find it more simple then other method.
X=120/100 Y.
X=6/5 Y.
Now X+Y=550.
And 6/5 Y+Y=550.
11Y/5=550.
Y/5=50.
Y=250.
Hope you would find it more simple then other method.
(1)
Sarat said:
1 decade ago
From the problem.
Total is 550.
x is 120% more than y.
Then x+y is (100+120)%.
Then 220/100*y = 550.
550*100/220 = 250.
y = 250.
Total is 550.
x is 120% more than y.
Then x+y is (100+120)%.
Then 220/100*y = 550.
550*100/220 = 250.
y = 250.
Pooja gupta said:
1 decade ago
x+y = 550.....(1).
x = 120% of y,
x = 120/100*y = >6/5*y,
Put he value in eq(1)we get,
6/5*y+y = 550,
(6y+5y)/5 = 550,
11y = 550*5,
y = 2750/11,
y = 250.
x = 120% of y,
x = 120/100*y = >6/5*y,
Put he value in eq(1)we get,
6/5*y+y = 550,
(6y+5y)/5 = 550,
11y = 550*5,
y = 2750/11,
y = 250.
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