Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 12)
12.
Two tailors X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
Answer: Option
Explanation:
Let the sum paid to Y per week be Rs. z.
Then, z + 120% of z = 550.
 z + |
120 | z = 550 |
| 100 |
| |
11 | z = 550 |
| 5 |
| z = |
 |
550 x 5 |  = 250. |
| 11 |
Discussion:
78 comments Page 3 of 8.
Amrutha said:
1 decade ago
@Vinoth.
This type of problems can be easily solved in the method posted by ramesh here we have to assume that y=100 and calculate the problem.
This type of problems can be easily solved in the method posted by ramesh here we have to assume that y=100 and calculate the problem.
Ram's power said:
7 years ago
@All.
Actually, given X+Y=550,
X=120%=120/100=6/5,
Then 6/5+Y=550,
Denominator 5 then,
(6+5y)=550,
11Y=550*5=2750,
Y=2750/11=250.
Actually, given X+Y=550,
X=120%=120/100=6/5,
Then 6/5+Y=550,
Denominator 5 then,
(6+5y)=550,
11Y=550*5=2750,
Y=2750/11=250.
Lalit said:
1 decade ago
Given,
X=120/100 Y.
X=6/5 Y.
Now X+Y=550.
And 6/5 Y+Y=550.
11Y/5=550.
Y/5=50.
Y=250.
Hope you would find it more simple then other method.
X=120/100 Y.
X=6/5 Y.
Now X+Y=550.
And 6/5 Y+Y=550.
11Y/5=550.
Y/5=50.
Y=250.
Hope you would find it more simple then other method.
(1)
Sarat said:
1 decade ago
From the problem.
Total is 550.
x is 120% more than y.
Then x+y is (100+120)%.
Then 220/100*y = 550.
550*100/220 = 250.
y = 250.
Total is 550.
x is 120% more than y.
Then x+y is (100+120)%.
Then 220/100*y = 550.
550*100/220 = 250.
y = 250.
Harish said:
6 years ago
120%=120/100 = 6/5.
If y is paid 1 rupee then 6/5 rupee is paid to x.
x:y = 6/5 : 1.
X:y = 6:5,
Therefore y share is 550*5/11 =250.
If y is paid 1 rupee then 6/5 rupee is paid to x.
x:y = 6/5 : 1.
X:y = 6:5,
Therefore y share is 550*5/11 =250.
Savarimuthu raja said:
6 years ago
Z+120/100z = 550.
Z(1+120/100) = 550.
Z(100+120/100) = 550.
Z(220/100) = 550.
Z(11/5) = 550.
Z = (550*5/11).
Z = 2750/11.
Z = 250.
Z(1+120/100) = 550.
Z(100+120/100) = 550.
Z(220/100) = 550.
Z(11/5) = 550.
Z = (550*5/11).
Z = 2750/11.
Z = 250.
Ganesh said:
1 decade ago
Let Y paid amount is RS = A.
Then X amount is = (120/100)*A.
Given X+Y = 550.
Substitute,
A+ 12/10 A = 550.
22A = 5500.
A = 250.
Then X amount is = (120/100)*A.
Given X+Y = 550.
Substitute,
A+ 12/10 A = 550.
22A = 5500.
A = 250.
Prathibha said:
5 months ago
Given :x + y = 550 ,
y = 550 - x,
x = (120*y)/100,
x = (120*550-x)/100,
x = 66000/220,
x = 300,
y = 550 - 300 = 250.
y = 550 - x,
x = (120*y)/100,
x = (120*550-x)/100,
x = 66000/220,
x = 300,
y = 550 - 300 = 250.
(5)
Praveensunny said:
1 decade ago
From the question x=120% of y.
By substituting the ans y value 200, 250 and 300 we will get X by adding X+Y=550 :).
By substituting the ans y value 200, 250 and 300 we will get X by adding X+Y=550 :).
GOWTHAM said:
7 years ago
Total X+Y=550rs,
Y=550-X,
By questions:
X=(120/100)*(550-X)---> eq(1)
By solving equations(1).
X=300rs.
Y=250rs.
Y=550-X,
By questions:
X=(120/100)*(550-X)---> eq(1)
By solving equations(1).
X=300rs.
Y=250rs.
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