Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 12)
12.
Two tailors X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
Answer: Option
Explanation:
Let the sum paid to Y per week be Rs. z.
Then, z + 120% of z = 550.
 z + |
120 | z = 550 |
| 100 |
| |
11 | z = 550 |
| 5 |
| z = |
 |
550 x 5 |  = 250. |
| 11 |
Discussion:
78 comments Page 2 of 8.
Adnan said:
9 years ago
The ratio between the present ages of Amir and Rehman is 6 : 7. If Rehman is 4 years older than Amir, what will be the ratio of the ages of Amir and Rehman after 4 years?
Solve and find the answer.
Solve and find the answer.
Krishn said:
6 years ago
X is gaining 20% more than y.
X ------> Y
5 ------> 6.
5 + 6 = 11.
11>>>>>550.
1 >>>>>>50.
5 >>>>>>250.
( 6 is 120% of 5).
X ------> Y
5 ------> 6.
5 + 6 = 11.
11>>>>>550.
1 >>>>>>50.
5 >>>>>>250.
( 6 is 120% of 5).
Vaidehi said:
5 years ago
If y get 100 and x get 120.
So sum of 100 and 120 is 220.
Now we directly get answer see,
If total is 220 so y get 100.
If total is 550 so y get ?
Let's solve it;
550*100/220 = 250.
So sum of 100 and 120 is 220.
Now we directly get answer see,
If total is 220 so y get 100.
If total is 550 so y get ?
Let's solve it;
550*100/220 = 250.
(2)
Prabhakar Sudha said:
8 years ago
Let the payment made to y be re.k,
Then the payment made to x will be 120%of re.k =re.1.2k
Now total payment is (k+1.2k)=2.2k, which is equal to 550.
So, 2.2k=550,
or,k=250 answer.
Then the payment made to x will be 120%of re.k =re.1.2k
Now total payment is (k+1.2k)=2.2k, which is equal to 550.
So, 2.2k=550,
or,k=250 answer.
Muhammad Anas Waheed said:
1 decade ago
It's all about substitution guys. Very easy!
x+y = 550.
x = (120/100)*y.
Simply by substituting the values of x into y, we get:
550-y = (120/100)y.
Hence y = 250 :).
x+y = 550.
x = (120/100)*y.
Simply by substituting the values of x into y, we get:
550-y = (120/100)y.
Hence y = 250 :).
Pooja gupta said:
1 decade ago
x+y = 550.....(1).
x = 120% of y,
x = 120/100*y = >6/5*y,
Put he value in eq(1)we get,
6/5*y+y = 550,
(6y+5y)/5 = 550,
11y = 550*5,
y = 2750/11,
y = 250.
x = 120% of y,
x = 120/100*y = >6/5*y,
Put he value in eq(1)we get,
6/5*y+y = 550,
(6y+5y)/5 = 550,
11y = 550*5,
y = 2750/11,
y = 250.
Rahul said:
6 years ago
Given,
X+Y=550........(1).
X is 120% of Y, so we can write X=1. 2Y........(2).
Solution: Put (2) in (1).
Y+1.2 Y=550.
2.2 Y = 550.
Y = 5500/22.
Y = 250.
X+Y=550........(1).
X is 120% of Y, so we can write X=1. 2Y........(2).
Solution: Put (2) in (1).
Y+1.2 Y=550.
2.2 Y = 550.
Y = 5500/22.
Y = 250.
Jane said:
12 months ago
Let the sum paid to Y be 100% and already given that sum paid to X is 120%.
Total sum = 550
120%+100% = 550
220%v= 550.
Then 100%=x.
x = 550*100/220 = 250.
Total sum = 550
120%+100% = 550
220%v= 550.
Then 100%=x.
x = 550*100/220 = 250.
(31)
Venom said:
10 years ago
1st statement: Total of X+Y = 550.....(1).
2nd statement: X = (120/100)Y = 6Y/5.....(2).
Substituting (2) in (1), we get:
(6Y/5 + Y) = 550.
Thus Y = 250.
2nd statement: X = (120/100)Y = 6Y/5.....(2).
Substituting (2) in (1), we get:
(6Y/5 + Y) = 550.
Thus Y = 250.
Naveed said:
8 years ago
x + y = 550 ......... (1).
x = 120% y.
x = 120 / 100 y = 1.2 y ...... (2).
Put in Equation 2 in 1,
1.2 y + y = 550.
2.2 y = 550.
y = 550 / 2.2 = 250.
x = 120% y.
x = 120 / 100 y = 1.2 y ...... (2).
Put in Equation 2 in 1,
1.2 y + y = 550.
2.2 y = 550.
y = 550 / 2.2 = 250.
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