Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 15)
15.
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
Answer: Option
Explanation:
Increase in 10 years = (262500 - 175000) = 87500.
| Increase% = |  |
87500 | x 100 |  % = 50%. |
| 175000 |
 Required average = |
|
50 | % = 5%. |
| 10 |
Discussion:
96 comments Page 8 of 10.
Satwika said:
9 years ago
Why should we take 17,5000 in denominator why not 26,25000?
Rahul said:
1 decade ago
@vijay.
Ya you are right vijay. Watt aparna did is wrong.
Ya you are right vijay. Watt aparna did is wrong.
Ak123 said:
1 decade ago
Why is 87,000 divided by 1,75,000? can someone explain.
Pallavi said:
6 years ago
Hi, I am not getting this. Please, someone, help me.
Mathu said:
9 years ago
Why we can't use 262500. To divide the number 87500.
Jagadeesh said:
1 decade ago
What is required average? Why it is divided by 10?
Reeta said:
1 decade ago
What is required average? Why it is divided by 10?
Prince said:
7 years ago
But using the formula we get the answer is 4.137.
Ankan Mondal said:
4 years ago
Sir, I cannot understand. Anyone explain, please.
(4)
Naveen Kumar said:
4 years ago
100-(20+60+10) = 10%.
10% = 30 means 100% = 300.
10% = 30 means 100% = 300.
(2)
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