Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 15)
15.
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
Answer: Option
Explanation:
Increase in 10 years = (262500 - 175000) = 87500.
| Increase% = |  |
87500 | x 100 |  % = 50%. |
| 175000 |
 Required average = |
|
50 | % = 5%. |
| 10 |
Discussion:
96 comments Page 7 of 10.
Sunil said:
1 decade ago
1,20,000 is the right answer.
138915 = X(1+5/100)^(10).
Calculate X = 1,20,000.
138915 = X(1+5/100)^(10).
Calculate X = 1,20,000.
Sukumar Natarajan said:
4 years ago
Here, we have to use the formula P = (1+r/100) ^n.
So, the Answer is: 4.23%.
So, the Answer is: 4.23%.
(14)
Yoga said:
1 month ago
Why aren't we using the formula of P (1+R/100) ^N? Please explain to me.
Prashant said:
3 weeks ago
Anyone, explain me, why we are not using compounding? Please clarify it.
(1)
Sheshu said:
1 decade ago
%increase=difference/lowvalue*100.
%decrease=difference/highvalue*100.
%decrease=difference/highvalue*100.
Mohsin said:
9 years ago
10% is equal to 30.
While 100% is equal to?
Then,
30 * 100/10 = 300.
While 100% is equal to?
Then,
30 * 100/10 = 300.
AgentSteel said:
10 years ago
20 + 60 + 10 = 90%,
Rem 10% = 30,
Therefore, total salary = 300.
Rem 10% = 30,
Therefore, total salary = 300.
Rajesh said:
10 years ago
Why 175000 is taken in the denominator instead of taking 2,62,500?
Aparna said:
1 decade ago
How 50/10 came in the last step. Can anyone help me to understand?
Karunakar said:
4 years ago
How do you know for taking the 10 years? Please explain me.
(3)
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