Aptitude - Percentage - Discussion

Discussion Forum : Percentage - General Questions (Q.No. 15)
15.
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
4.37%
5%
6%
8.75%
Answer: Option
Explanation:

Increase in 10 years = (262500 - 175000) = 87500.

Increase% = 87500 x 100 % = 50%.
175000

Required average = 50 % = 5%.
10

Discussion:
93 comments Page 6 of 10.

Shru said:   9 years ago
Guys it's very simple, here they used the formula for % change that is =difference in % ÷ initial value * 100.

SamuelAA said:   10 years ago
If a number is 20% more than the other, how much percent is less than the first?

Can somebody solve this please?

Keshav said:   9 years ago
@Aparna,

20% + 60% + 10% = 90%.

Means rest 10% = 30 rupee.

So obviously his salary will be 300 (100%).

Bluespark said:   1 decade ago
@ak123
%increase=(increase*100)/year its a formula since u r finding the increase % of 175000, yr=175000

Sneha said:   10 years ago
May be it is:

a-0.25 x = c.
b-0.20 x = c.

a-0.25 x = b-0.20 x.
a-0.45 x = b.
a is 45% greater than b.

Naren said:   1 decade ago
Ya vijay is correct....

Let his expenses 20+60+10=90

Remaining money 30, means 10%=30, Then 100%=300

Sunil vishwakarma said:   1 decade ago
10 is because there is formula of 2 years, p(1+r/100)^t, where t is for next 2 year, is 2*5 = 10.

Vikrala said:   10 years ago
There's a shortcut here i.e 100*r/100+r = 100*20/100+20.

You can easily get the result.

Riad said:   6 years ago
Suppose,
Salary = x.

(100-90)% of x = 30.
10/100 * x = 30.
x = 30*100/10.
x = 300.

Rekha said:   7 years ago
But there was not mentioned exactly 10 years. Can you please explain how it came?


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