Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 15)
15.
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
Answer: Option
Explanation:
Increase in 10 years = (262500 - 175000) = 87500.
| Increase% = | ![]() |
87500 | x 100 | % = 50%. |
| 175000 |
Required average = |
![]() |
50 | % = 5%. |
| 10 |
Discussion:
96 comments Page 9 of 10.
Suman said:
1 decade ago
Thanku Naren you gave a very shortcut method.
Shashi said:
1 decade ago
Dear, @Anil.
What is the third number?
What is the third number?
Saravanan said:
1 decade ago
How to say it's 10 years difference?
Prakash singha said:
7 days ago
Nice, Thanks for explaining.
Sreekanth said:
9 years ago
Anyone explain how 50/10?
Saiswarupa said:
8 years ago
Thank you @Nikhil Dasari.
Muskan said:
4 years ago
Same here @Ankan Mondal.
T Muvetha said:
2 years ago
A decade means 10 years.
(15)
Anil said:
8 years ago
Why we divided 50 by 10?
Bunny said:
7 years ago
Why you take (50/10)%?
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% = 50%.
Required average =