Aptitude - Percentage - Discussion

How (50/10)%?

Population in 2001 = 138915
Population in 1998 was = 138915 * 100/105 * 100/105 * 100/105 = 1,20,000.

Had it given the population in 1998 = 1,20,000 then what will be the population in 2001, if it increases @5% PA.

The solution would be = 1,20,000 * 105/100 * 105/100 * 105/100 = 138915 (population in 2001).

percentage increase = (increased quantity/initial quantity) * 100.

As given above problem.

Increased quantity = 262500 - 17500.
= 87500
Percentage increase = (87500/175000) * 100.
= 50% per decade means for 10 years.

Per one year = 50/10 = 5%.

In an election between two candidates, 75% of the voter's caste their votes, out of which 2% of the votes were declared invalid. A candidate got 9261 votes which were 75% of the total valid votes. Find the total number of votes enrolled in that election.

Can anyone solve this?

Hi @Jayakumar s

let the total number of votes = x
no.of votes cast = 75% of x
The valid votes = 98% of (no.of votes cast)
i.e 98% of (75% of x) (here 2% is invalid so (100-2)%=98%)

Then (A candidate got 75% of valid votes =9261)
75% of (98% of (75% of x) = > 75/100 * 98/100 *75/100 * x =9261.
= > (9261*100*100*100) / (75*98*75),
= > 9261000000 / 551250,
= >16800.

We can also solve with options.

A) 4.37 % 175000 = 7647.5.
So decade means 10 year.
multiply 10*7647.5= 76475.
and add the multiply result with the 175000.
i.e)76475+175000 =2514755% 17500.
So it's not matching.

B) 5% 175000 = 8750.
so decade means 10 year.
multiply 10*8750= 87500.
and add the multiply result with the 175000.
i.e)87500+175000 = 262500.

Its right so answer is B.

Percentage formula.

% = [final value-intial value/intial value] * 100.
% = 87500/17500 * 100.
= 5 is the ans hence proved.

Good @Shivani.

Why we divided 50 by 10?

Suppose man's salary =100 Rs.

20%=20 Rs rent,
60% =60 Rs Expense,
10% =10 Rs LIc,
so left amount for education=100-(20+60+10)=10,
10% left ie 10 Rs of 100 %,
10%= 30(In qs),
1% =30/10,
100% =30*100/10=300(salary).