Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 15)
15.
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
Answer: Option
Explanation:
Increase in 10 years = (262500 - 175000) = 87500.
| Increase% = |  |
87500 | x 100 |  % = 50%. |
| 175000 |
 Required average = |
|
50 | % = 5%. |
| 10 |
Discussion:
93 comments Page 10 of 10.
T Muvetha said:
1 year ago
A decade means 10 years.
(13)
Priyanka said:
1 year ago
The population increased in 10 years 262500 - 175000 = 87500. For a decade that is for 10 years
Per year increase 87500/10= 8750.
Avg per cent increase in population per year= 8750/175000*100 = 5 per cent.
Per year increase 87500/10= 8750.
Avg per cent increase in population per year= 8750/175000*100 = 5 per cent.
(28)
Siddhant said:
10 months ago
262500 = x% of 175000
i.e. 150% of 175000
Thus, a 50% increase from 100%.
50% increase in 10 years, so 5% increase per year.
i.e. 150% of 175000
Thus, a 50% increase from 100%.
50% increase in 10 years, so 5% increase per year.
(7)
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