Aptitude - Percentage - Discussion

Discussion Forum : Percentage - General Questions (Q.No. 15)
15.
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
4.37%
5%
6%
8.75%
Answer: Option
Explanation:

Increase in 10 years = (262500 - 175000) = 87500.

Increase% = 87500 x 100 % = 50%.
175000

Required average = 50 % = 5%.
10

Discussion:
93 comments Page 5 of 10.

Mathu said:   9 years ago
Why we can't use 262500. To divide the number 87500.

Keshav said:   9 years ago
@Aparna,

20% + 60% + 10% = 90%.

Means rest 10% = 30 rupee.

So obviously his salary will be 300 (100%).

Aman said:   9 years ago
Population of town is increased by 5% annually. If its population in 2001 was 138915. What it was in 1998.

In this question what is the formula?

@Sunil I don't know where you derive your formula.

Angelo said:   9 years ago
What is the answer, if the population of the town is increased by 5% annually. If its population in 2001 was 138915. Then What was it in 1998?

Please anyone solve this.

Sreekanth said:   9 years ago
Anyone explain how 50/10?

Surya said:   9 years ago
Decade means?

Ann said:   9 years ago
I think the official answer is wrong : if you increase a population of 175,000 by 5% each year during 10 years it becomes more than 262,500.

Proof 175,000 * (1.05 ^ 10) = 285'056.56 that's more then 262,500!

So it should be less than 5%.

Right answer : ( (262,500/175,000) ^ 0.1) - 1 = 4.137974%.

So, A mus be the right choice.
(2)

Mohsin said:   9 years ago
10% is equal to 30.

While 100% is equal to?
Then,
30 * 100/10 = 300.

Satwika said:   9 years ago
Why should we take 17,5000 in denominator why not 26,25000?

Shru said:   9 years ago
Guys it's very simple, here they used the formula for % change that is =difference in % ÷ initial value * 100.


Post your comments here:

Your comments will be displayed after verification.