Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 78)
78.
What will be remainder when 17200 is divided by 18 ?
Answer: Option
Explanation:
When n is even. (xn - an) is completely divisibly by (x + a)
(17200 - 1200) is completely divisible by (17 + 1), i.e., 18.
(17200 - 1) is completely divisible by 18.
On dividing 17200 by 18, we get 1 as remainder.
Discussion:
27 comments Page 1 of 3.
Samridhi shah said:
3 years ago
What if the power was odd no, for ex 17 power 137?
How to solve that?
How to solve that?
(2)
Meezab e rehmat said:
4 years ago
@All.
Here, -1 means 1 is the remainder.
And 18=17+1.
Here, -1 means 1 is the remainder.
And 18=17+1.
HRK said:
4 years ago
@All.
the Simple logic is;
18 = 9*2.
Given a number in the question is divisible by 2 as it will have 0 in the unit digit.
Now checking for 9, 17 = 1+7 = 8, but this is not divisible by 9.
To make it divisible add 1 in the unit digit, i.e. 1+7+1 (the number be like 170000.....1)
So this added number is the remainder.
the Simple logic is;
18 = 9*2.
Given a number in the question is divisible by 2 as it will have 0 in the unit digit.
Now checking for 9, 17 = 1+7 = 8, but this is not divisible by 9.
To make it divisible add 1 in the unit digit, i.e. 1+7+1 (the number be like 170000.....1)
So this added number is the remainder.
Jigsa said:
5 years ago
x^n +1 is divisible by (X+1) when n is odd.
Kaveri said:
5 years ago
When 17^200 is completely divisible by 18 then the remainder needs to be 0 right, then how come 1?
Lakshmi said:
6 years ago
I don't understand, please explain it.
Ravikumar Chauhan said:
6 years ago
But from where 1^200 come?
17^200 is same or has the same value 17^200-1^200.
Please explain.
17^200 is same or has the same value 17^200-1^200.
Please explain.
(1)
Sekhar said:
6 years ago
What is the remainder when 83^63 is divided by 14.
Hamsa said:
6 years ago
What is the remainder when 79^59 is divided by 40.
Praful kumar said:
7 years ago
@All.
Simple, it is solved by;
Rule1: If a^even no. ÷ a+1, then the remainder will always be 1.
Rule2: If a^odd no. ÷ a+1, then the remainder will always be a.
Rule3: If a^n. ÷ a-1, then the remainder will always be 1, whether n is even or odd.
Simple, it is solved by;
Rule1: If a^even no. ÷ a+1, then the remainder will always be 1.
Rule2: If a^odd no. ÷ a+1, then the remainder will always be a.
Rule3: If a^n. ÷ a-1, then the remainder will always be 1, whether n is even or odd.
(1)
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