Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 78)
78.
What will be remainder when 17200 is divided by 18 ?
17
16
1
2
Answer: Option
Explanation:

When n is even. (xn - an) is completely divisibly by (x + a)

(17200 - 1200) is completely divisible by (17 + 1), i.e., 18.

   (17200 - 1) is completely divisible by 18.

   On dividing 17200 by 18, we get 1 as remainder.

Discussion:
27 comments Page 1 of 3.

Akhil said:   1 decade ago
Why cant it be (17^200-2^200) is completely divisible by 17+2=19 ?

Gururaj said:   1 decade ago
Simple way way is:

17 ^2 %18 =1.

(17^2)*(7^100) %18 will also be 1.

Siddeswara Reddy said:   1 decade ago
When (X-1)^n is divided by X then R=1, If n is even natural number and if n is odd natural number then R = X-1.

Swapnil said:   1 decade ago
How can we write 17^200-1^200 this one is not equals to 17^200.

We can write 18 as 17+1 but why we take 17^200-1.

Anusha said:   1 decade ago
(17*17*17*......*17) /18.

18-17 = 1.

(-1*-1*-1*.....*-1) /18.

Power is even so, 1/18.

Answer is 1 (numerator).

Prasanna Kartik said:   1 decade ago
Hi guys,

We can solve it by negative reminders concept.

Here is our question 17^200 is divided by 18.

17/18 negative reminder is -1. So (-1) ^200=1.

Example 11/3 positive reminder as we know is 2 and the negative reminder is -1(11-12).

Gaurav said:   10 years ago
11/3 reminder is 2 but what is -1(11-12)? Please explain more.

Bharath said:   9 years ago
17^200 = (18 - 1)^200 gives (18^200) - 2 * 18 + 1 which give remainder 1 when divided by 18.

Mir Rokon Uddin said:   9 years ago
It is notable that the power of 17 is even.

So we can consider 17^2 and divide it by 18. And we got 1 as a reminder. So the answer is 1.

Dev said:   9 years ago
Please give me solution for finding the value of R. And explain the answer.

26^57÷29 = R.
128^100÷153 = R.
2^187÷51 = R.
17^14÷72 = R.


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